Answer is the last choice
2a-4/1= -a-1/a-4
Cross multiply
(2a-4)(a-4)= -(a-1)
2a^2-8a-4a+16= -a+1
Bring right to left sign change signs
2a^2-8a-4a+16+a-1=0
Combine like terms
2a^2-11a+15=0
a= 2 b= -11 c= 15
Use quadratic formula
-b+-sq rt of b^2-4ac. Divided by 2a
-(-11) +- 11^2-4(2)(15) divided by 2(2)
11+-sq rt 121-120 divided by 4
11+1 /4. 11-1/4
12/4. 10/4
3. , 5/2
I'm pretty sure its c I dont really understand stand what its asking
Answer:
there is no number for that,there is infinite stars in the universe
110*0.6=66 blue blocks
110*0.1=11 green blocks
