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3 years ago

I’m giving a lot of points!!!!!I’ll mark brainliest fast please!!!!!!!

Mathematics

1 answer:

Sergeeva-Olga [200]3 years ago

3 0

Answer:

63 ft^2

Step-by-step explanation:

The hole is the rectangle minus the area of the triangle.

The area of the rectangle is

A =l*w

A = 12*6

=72

The area of the triangle is

A = 1/2 b*h

= 1/2 (3*6)

= 9

A rectangle - A triangle = A hole

72 - 9

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Find the value of x<br><br> 3/4 x-4=8

Vesna [10]

Answer: x = 16

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable. :)

7 0

2 years ago

3.28×3=9.84 why is this

-Dominant- [34]

3.28·3 = 9.84 is the same as:
3.28+3.28+3.28 = 9.84

Hope this helped! Good luck!

5 0

3 years ago

Which of the following graphs represents the equation y- 4 =3(x-1)

Leno4ka [110]

Answer:D

Step-by-step explanation:y-4=3(x-1)

y-4=0 3(x-1)

y=-4 , 3x-3

y=-4=3x-3

3 3

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6 0

2 years ago

Read 2 more answers

An article presents voltage measurements for a sample of 66 industrial networks in Estonia. Assume the rated voltage for these n

kramer

Answer:

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 232 V

Sample mean, $\bar{x}$ = 231.5 V

Sample size, n = 66

Sample standard deviation, s = 2.19 V

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 232\\H_A: \mu \neq 232$

We use Two-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} }$ Putting all the values, we have

$t_{stat} = \displaystyle\frac{231.5- 232}{\frac{2.19}{\sqrt{66}} } = -1.8548$

Now,

$t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = \pm 1.9971$

Since,

$|t_{stat}| > |t_{critical}|$

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

4 0

2 years ago

In an expression<br>(8/9) squared (-81)+3/5dividedby-9/10

Nitella [24]

If you wanted to calculate it, there it is:
$(\frac{8}{9})^2 (-81)+\frac{\frac{3}{5}}{\frac{-9}{10}} = \frac{64}{81}*(-81)+\frac{3}{5}*\frac{10}{-9} = -64+\frac{-2}{3}= \\ =-64-\frac{2}{3}=\frac{-192-2}{3}=\frac{-194}{3}$

6 0

3 years ago

Read 2 more answers