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Lera25 [3.4K]
3 years ago
9

Factor greatest common factor 6a^6+24a^3

Mathematics
1 answer:
lozanna [386]3 years ago
3 0
55 is the answer hope it helps
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WILL GIVE BRAINLIEST TO FIRST PERSON TO ANSWER CORRECTLY! PLUS 35 POINTS!
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4 years ago
Please help very urgent
Alik [6]

Answer:

32, <u>16</u>, <u>8</u>, <u>4</u>, <u>2</u>, 1

Explanation:

The geometric mean can be represented by \sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}.

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

a_{n} = a_{1} • r^{n-1}

Where a_{n} is the nth term, a_{1} is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, a_{1} will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

\sqrt[5]{\frac{a_{6}}{a_{1}}} =

\sqrt[5]{\frac{1}{32}} =

\frac{1}{2}.

Therefore: r = \frac{1}{2}.

Using all the information we have, we can find the explicit rule:

a_{n} = a_{1} • r^{n-1}

  • a_{1} = 32
  • r = \frac{1}{2}

a_{n} = a_{1} • r^{n-1} →

\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

a_{1} = 32 • (\frac{1}{2})^{1-1}

a_{1} = 32 • (\frac{1}{2})^{0}

a_{1} = 32 • 1

a_{1} = 32

a_{6} = 32 • (\frac{1}{2})^{6-1}

a_{6} = 32 • (\frac{1}{2})^{5}

a_{6} = 32 • \frac{1}{32}

a_{6} = 1

3 0
3 years ago
Read 2 more answers
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lukranit [14]
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Predict the next three numbers in the pattern. 4 comma 2 comma 1 comma one half comma one fourth ​,
kolbaska11 [484]
I think that the next numbers are 1/3, 1/5 and 1/6
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4 years ago
Jeff has two sticker-printing machines. Each machine can print 42 stickers per minute. On day 1, only the first machine was used
Anna71 [15]

Answer:

c 89+42x+42y

Step-by-step explanation:

On day 1 :

First Machine= 89 stickers

Second Machine= none

On day 2 :

First Machine= ? stickers ( if in 1min = 42stickers

x min=?

( x min/1 min × 42stickers)

=42x stickers.

Second Machine=?stickers ( if in 1min = 42stickers

y min=?

( y min/1 min × 42stickers)

=42y stickers.

Total = 89 + 42x + 42y

5 0
3 years ago
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