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Yuliya22 [10]
3 years ago
9

If a die is rolled 40 times, there are 640 different sequences possible. The following question asks how many of these sequences

satisfy certain conditions. HINT [Use the decision algorithm discussed in Example 3 of Section 6.3.] What fraction of these sequences have exactly five 1s? (Round your answer to four decimal places.)
Mathematics
1 answer:
RideAnS [48]3 years ago
4 0

Answer:

0.1433

Step-by-step explanation:

<h3><u>All possibilities:</u></h3>

The total number of different sequences in 40 rolls of a die is 6^{40}

<h3><u>Exactly five 1s in 40 rolls:</u></h3>

                         The 1s may occur at any 5 rolls among 40. The number of ways of exactly five 1s occuring is therefore, equivalent to number of ways of selecting 5 fruits from 40 distinct fruits which is ⁴⁰C₅ ways. These 5 rolls have a fixed outcome <u>1</u>. Other 35 rolls each have 5 possible outcomes : <u>2</u> or <u>3</u> or <u>4</u> or <u>5</u> or <u>6</u>. So, the number of possible sequences of outcomes on other 35 rolls of the die is 5^{35}.

⇒The total number of different sequences having exactly five 1s in 40 rolls of a die is (⁴⁰C₅)×(5^{35})

∴The fraction of the total number of sequences having exactly five 1s is \frac{(⁴⁰C₅)×([tex]5^{35})}{6^{40}}[/tex] ≈ <u>0.1433</u>

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