Answer:
Step-by-step explanation:
A horizontal line is a "y = " line. So the horizontal line that goes through the point given has the equation y = -1 (-1 being the y coordinate of the point). That means that another point on this line, y = -1, will also have to have a y coordinate of -1. The only one is the last one, (-2, -1).
Answer:
see explanation
Step-by-step explanation:
Given
a = ![\left[\begin{array}{ccc}3\\2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C2%5C%5C%5Cend%7Barray%7D%5Cright%5D)
To obtain -3a multiply each of the elements of a by -3
3a = ![\left[\begin{array}{ccc}-3(3)\\-3(2)\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%283%29%5C%5C-3%282%29%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}-9\\-6\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-9%5C%5C-6%5C%5C%5Cend%7Barray%7D%5Cright%5D)
To obtain 1.5a multiply each element by 1.5
1.5a = ![\left[\begin{array}{ccc}1.5(3)\\1.5(2)\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1.5%283%29%5C%5C1.5%282%29%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}4.5\\3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4.5%5C%5C3%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Answer:
let's say cells is c and hours are x that means there are 15 cells each hour. the equation for that is c=15x
after 08 hours the cells have multiplied 8 times their original size. meaning that the equation changes to this: c=15x x=8 c= 15(8)
x equals 8 at that time.. literally
ok the cells have multiplied and now there are 120 cells in total
then after one day the cells have multiplied over 12 times afterwards. now x equals 24. the equation would look a little like this:
c=15x x=24 c= 15(24)
there are 360 cells now.
Explain in your own words the relationship between x=8 with x=24 in the equation.
Answer:
an = 4n +5
Step-by-step explanation:
First we need to find a common difference
d = a2-a1 = 13-9 = 4
The formula for an
an =a1+d(n-1)
an = 9 + 4(n-1)
Distributing
an = 9+4n-4
Combine like terms
an = 4n +5
