Answer:
Option 2: (1, 0) and (0, -5)
Step-by-step explanation:
Let's solve this system of equations using the elimination method.
Start by labelling the two equations.
5x -y= 5 -----(1)
5x² -y= 5 -----(2)
(2) -(1):
5x² -y -(5x -y)= 5 -5
Expand:
5x² -y -5x +y= 0
5x² -5x= 0
Factorise:
5x(x -1)= 0
5x= 0 or x -1= 0
x= 0 or x= 1
Now that we have found the x values, we can substitute them into either equations to solve for y.
Substitute into (1):
5(0) -y= 5 or 5(1) -y= 5
0 -y= 5 or -y= 5 -5
y= -5 or -y= 0
y= 0
Thus, the solutions are (0, -5) and (1, 0).
Answer: 1
Step-by-step explanation:
From the given picture, it can be seen that there is a plane H on which two pints J and K are located.
One of the Axiom in Euclid's geometry says that <em>"Through any given two points X and Y, only one and only one line can be drawn "</em>
Therefore by Axiom in Euclid's geometry , for the given points J and K in plane H , only one line can be drawn through points J and K.
Answer:
Step-by-step explanation:
non linear because linear has always to the first power
<span>Answer:
{(3,7),(3,8),(3,-2),(3,4),(3,1)} A.Domain:{3} Range:{-2,1,4,7,8}**** B.Domain:{-2,1,4,7,8}</span>
Answer:
-z+4=-4
Step-by-step explanation:
First, you want to move the positive four to the other side to isolate the variable.
-z=-8
You cannot have a negative variable, so divide both sides by 1.
-z/1=-8/1
Your answer would be:
Z=8
Hope this helps!!
