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forsale [732]
3 years ago
15

Solve the system of equations

Mathematics
1 answer:
dlinn [17]3 years ago
7 0

Answer:

What's the problem?

Step-by-step explanation:

No picture or you don't say anything.

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Slove the absolute value equation I3xI=18
Rama09 [41]
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3 years ago
How many solutions are there for the system x^2+4y^2=100 and 4y-x^2=-20
never [62]
There are 5 solutions for this system.

x^2 + 4y^2 = 100  ____1
4y - x^2 = -20  ____2
Add both 1 & 2 together. x^2 gets cancelled
4y^2 + 4y = 80   (send 80 to the other side and divide by 4)
Then equation the becomes : y^2 + y -20 =0
Now factorise the equation: (y+5) (y-4) = 0
Solve for y :  y = -5 and y = 4
Using the values of y to find the values of x. From equation 1:
x^2 = 100 - 4y^2    x = /100 - 4y^2  (/ means square root) Replace values of y
y = -5, x = /100 - 4(-5)^2 = /100 - 100 = 0
y = 4, x = /100 - 4(4)^2 = / 100 - 64 = /36 = -6 or 6
Thus we have 6 solutions y = -5, 4 and x = -6, 0, 6
6 0
3 years ago
Solve for X.Enter the solutions from least to greatest.
FinnZ [79.3K]

Answer:

lesser x= -10.32

greater x= -3.68

Step-by-step explanation:

- 7 +  \sqrt{11}  =  - 3.68

- 7 -  \sqrt{11}  =  - 10.32

4 0
3 years ago
Read 2 more answers
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