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victus00 [196]
2 years ago
9

Chef Alonso is creating a recipe called Spicy Italian chicken with the following ingredients:3/4 pound chicken, 2 1/2 cups tomat

o sauce, 1 teaspoon oregano, and 1/2 teaspoon of his special hot sauce. What is the number Chef Alonso should multiply the amount of chicken by so that the recipe will make 2 full servings, each with 1/2 pound of chicken
Mathematics
2 answers:
Yuri [45]2 years ago
4 0

Answer:

1. He wants 1/2 pound of chicken so one complete serving. The remainder is 1/4, half of a half is one fourth so the answer is 1 and a half servings.

2. (n ×3/2) ×2 n being the original amount the recipe calls for

3. Use the formula to solve

4.yes oregano, no for the hot sauce. Use the formula to show your work




Tatiana [17]2 years ago
3 0
If one serving is 1/2 a pound and the recipe uses 3/4, then the recipe must be multiplied by 1 1/3 to make 1 pound of chicken - 2 servings
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a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l
GrogVix [38]

Answer:

\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}

Step-by-step explanation:

The equation of a line:

y=mx+b

We have

m=\dfrac{2}{3}

substitute:

y=\dfrac{2}{3}x+b

The formula of a distance between a point and a line:

General form of a line:

Ax+By+C=0

Point:

(x_0,\ y_0)

Distance:

d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}

Convert the equation:

y=\dfrac{2}{3}x+b     |<em>subtract y from both sides</em>

\dfrac{2}{3}x-y+b=0    |<em>multiply both sides by 3</em>

2x-3y+3b=0\to A=2,\ B=-3,\ C=3b

Coordinates of the point:

(0,\ 0)\to x_0=0,\ y_0=0

substitute:

d=4

4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}

4=\dfrac{|3b|}{\sqrt{13}}\qquad|    |<em>multiply both sides by \sqrt{13}</em>

4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}   |<em>divide both  sides by 3</em>

b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}

Finally:

y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}

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