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iren2701 [21]
3 years ago
10

Will award brainliest answer!!!!A support beam needs to be placed at a 28° angle of elevation so that the top meets a vertical b

eam 1.6 meters above the horizontal floor. The vertical beam meets the floor at a 90° angle.Law of sines: Approximately how far from the vertical beam should the lower end of the support beam be placed along the horizontal floor?3.0 meters3.4 meters3.9 meters4.4 metersWhich equation is true for triangle QRS?
Mathematics
1 answer:
Andrews [41]3 years ago
3 0
3.4 meters because you can you use it sorry if misunderstood hope it helped.
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The supplement of an angle is four and a half times as large as the complement of the angle. What is the measure of the compleme
katovenus [111]

Answer:

25.71°

-by-step explanation:

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7 0
3 years ago
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Plz help fast!!!! will mark brainliest if correct
Marta_Voda [28]

Step-by-step explanation:

(g+f)(x) ie option B

-2+1 = -1

1-2 = -1

4-5 = - 1

7 0
3 years ago
The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t
shtirl [24]

Answer:

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

Step-by-step explanation:

As the given Augmented matrix is

\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 1 :

r_{1}↔r_{1} - r_{2}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 2 :

r_{3}↔r_{3} - 8r_{1}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]

Step 3 :

r_{2}↔\frac{r_{2}}{7}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]

Step 4 :

r_{1}↔r_{1} + 14r_{2} , r_{3}↔r_{3} - 124r_{2}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]

Step 5 :

r_{3}↔\frac{r_{3}. 7}{254}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]

Step 6 :

r_{1}↔r_{1} - 4r_{3} , r_{2}↔r_{2} + \frac{1}{7} r_{3}

\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]

∴ we get

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

6 0
3 years ago
Which is NOT true of a quadratic function? Please help asap!
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i know the answer to be "B" because we just learned this in class


7 0
3 years ago
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In a geometric sequence, the seventh term exceeds the fifth term by 1,920. Find the sum of
uranmaximum [27]
That's geometric sequence

T7 = T5*r^2 = T5+1920
r = 2, so

4*T5 = T5 + 1920
3T5 = 1920
T5 = 640

640 = 2^4 * 40

So, a=40 and the sequence is

40 80 160 320 640 1280 2560 5120 10240 20480 40960 ...

Note that 2560 = 640 + 1920


PLEASE DONT CLICK ON ANY LINKS ON HERE!! BE CAREFUL.
they lead to a virus pleade be careful.
6 0
3 years ago
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