It means that there are people who understand binary and those that do not understand it. That is, binary is said to be the way that computers are known to express numbers.
<h3>What is the joke about?</h3>
This is known to be a popular joke that is often used by people who are known to be great savvy in the field of mathematics.
The joke is known to be one that makes the point that a person is implying that the phrase is about those who only understands the decimal system, and thus relies on numbers in groups of 10.
The binary system is one that relies on numbers that are known to be in groups of 2.
Therefore, If the speaker of the above phrase is one who is able to understand binary, that person would be able to say that that the phrase is correctly written as "there are 2 types of people that understand binary".
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The answer is true. Data redundancies should be avoided,
because redundancy of information or encoded data, may cause inconsistencies
within the database itself and the system and also redundant information can
consume a lot of storage space and will just waste it, which is why it is
important to avoid data redundancy.
An IP address is mostly for your WIFI . Internet Protocol .
Overtype Mode is where you are making changes to text (putting in new characters)
Like when a seed drops on the ground, and a bee come to take some honey. It sticks to the bee and where the bee goes, the bee will rub it off and the seed will start to grow.
Answer:
C++ code for encryption is given below
Explanation:
#include <iostream>
using namespace std;
//functions to encrypt and decrypt
void encrypt(char str[]);
void decrypt(char str[]);
int main(){
char str[200];
bool done = false;
while(!done){
cout << "Enter a string (enter * to stop): ";
cin.getline(str, 200);
if(str[0] == '*' && str[1] == '\0')
done = true;
else{
encrypt(str);
cout << "Encrypted: " << str << endl;
decrypt(str);
cout << "Decrypted: " << str << endl;
}
cout << endl;
}
}
void encrypt(char str[]){
int i = 1;
for(int j = 0; str[j] != '\0'; j++){
str[j] += i;
i++;
if(i == 11)
i = 1;
}
}
void decrypt(char str[]){
int i = 1;
for(int j = 0; str[j] != '\0'; j++){
str[j] -= i;
i++;
if(i == 11)
i = 1;
}
}
