I would say D. Usually students aren't expected to fill out the FAFSA till junior or senior year, this is because it is based on household income which may change every year. Also, guidance counselor's can help students on the right track to go to classes. Clubs and/or sports teams look really good on college applications and are usually preferred by colleges.
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Answer:
(3) option is the correct answer.
Explanation:
Constructors need to initialize the object in the memory. "To declare the Constructor for any class the user needs to specify the constructor name which is already the class name". This is an object-oriented language guideline.
It is because the object is created by the name of the class and Constructor is used to allocate the memory for the object. hence Constructor is created by the name of the class.
For example--
class test //class name test
{
test() //created a constructor with class name "test"
{
}
}
In the above example class name and constructor name are same if it not then it will gives a error.
Another option is not valid for the answer to the above problem because-
- Option 1 is wrong because, for any class, the data member is a type of variable, which is used to store the data and is accessed with the help of an object.
- Option 2 is wrong because, for any class, member function is a type of user function used to accessed the variable and expressions.
- Option 4 is wrong because, package is a set used to hold classes and interfaces.
// C++ switch
// It can also be used for JAVA, C#
switch(age){
// here age will be sent by the function in which it is used
// case to check the age<2
case(age<2 && age>0):
// printing the line
cout<<"ineligible";
// case to check the age ==2
case(age==2):
// printing the line
cout<<"toddler";
// case to check 3-5
case(age>=3 && age<=5):
cout<<"early childhood";
// case to check 6-7
case(age==6 || age==7):
cout<<"young reader";
//case to check 8-10
case(age>=8 && age<=10):
cout<<"elementary";
// case to check 13
case(age==13):
cout<<"impossible";
//case tocheck 14-16
case(age>=14 && age<=16):
cout<<"high school";
// case to check 17 or 18
case(age==17 || age==18):
cout<<"scholar";
//case to check >18
case(age>18);
cout<<"ineligible";
// default case
default:
cout<<"Invalid age";
}
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Answer:
yes there is an answer to this question
