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Ymorist [56]
3 years ago
9

In this exercise, use the following variables : i,lo, hi, and result. Assume that lo and hi each are associated with an int and

that result refers to 0.
Write a while loop that adds the integers from lo up through hi (inclusive), and associates the sum with result.

Your code should not change the values associated with lo and hi. Also, just use these variables : i,lo, hi, and result.
Computers and Technology
1 answer:
Assoli18 [71]3 years ago
7 0

Answer:

result = 0

i = lo

while i <= hi:

       result = result + i

       i += 1

Explanation:

Initialize the <em>result</em> as 0 to hold the summation value.

Since we are asked not to change the value of <em>lo</em> and <em>hi</em>, our loop control variable is <em>i</em> and initially it starts from <em>lo.</em>

Since we are asked to add the number from <em>lo</em> to <em>hi, </em>while loop condition checks it.

While the condition satisfies (during each iteration), the value of <em>i</em> is added to the result and the value of <em>i</em> is incremented by one.

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Answer:

The solution code is written in R script.

  1. #string variable
  2. character_str<- "Hello World"
  3. #logical variable
  4. logic <-  a > b
  5. #Missing value
  6. myVec <-c(1, 2, 3, NA)
  7. #Use class to check data type
  8. class(character_str)
  9. class(logic)
  10. class(myVec)

Explanation:

A string variable is a variable that hold a string (the letters enclosed within quotation marks) (Line 2)

A logical variable is a variable that hold a logical value (either True or False). The logical value is created by comparing two variables (Line 5).

In R, missing value is an unknown value which is represented by NA symbol (Line 8).  

We can use in-built method <em>class </em> to check for the variable type in R (Line 11-13). For example, the output of <em>class(character_str)</em> is "<em>character</em>"

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In a networking context, "architecture" refers to
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Answer:

A well built netwrk

Explanation:

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3 years ago
The algorithm for solving the problem of average of five (5) numbers​
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Answer:

Explanation:

Denote the five numbers as a, b, c, d and e.

The average is:

(a + b + c + d +e) ÷ 5.

Easily:

Learn how to do input and output operations in your programming language of choice.

Learn what average is (see Arithmetic mean - Wikipedia)

Learn how to code arithmetic operations in your PL of choice.

Put all that together and code the program.

Oh, did you expect the code snippet? Sorry, I don’t do peoples’ homework for them on principle. Homework is for you to learn something. If you can’t be bothered, accept that you’ll fail your class. If you want to pass, LEARN.

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Which is the last step in conducting a URL search?
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The user's browser renders the html code as a visual web page
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A computing company is running a set of processes every day. Each process has its own start time and finish time, during which i
Helga [31]

Answer:

Above all else, let us show that this issue has the greedy choice property.

This implies that worldwide ideal arrangement can be gotten by choosing local ideal arrangements. Presently notice the following:

The global optimal solution of the issue requests us to track down the minimum number of times process_check module should be run.

It is likewise referenced that during each running interaction, process_check module should be called atleast once. Along these lines, the minimum possible number of process_check calls happens when process_check is made close to the quantity of the processes that are run.

Along these lines, we see that the global optimal solution is shaped by choosing optimal answer for the nearby advances.

Along these lines, the issue shows greedy choice property. Thus, we can utilize a greedy algorithm for this issue.

The greedy step in this calculation is to postpone the process_check as far as might be feasible. Thus, it should be run towards the finish of each interaction. So the following algorithm can be utilized:

Sort the cycles by utilizing the completion times.

Towards the finish of the 1st process in the arranged list, run the process_check module. Right now any process that is now running is removed the arranged rundown. The main interaction is additionally removed from the sorted list.

Now repeat stage 2, till all processes are finished.

In the above mentioned algorithm, the costliest advance is the step of sorting. By utilizing the optimal sorting algorithm, for example, merge sort, we can achieve it in O(n log n) asymptotic time.

Along these lines, this greedy algorithm additionally takes O(n log n) asymptotic time complexity.

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3 years ago
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