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dimulka [17.4K]
3 years ago
12

PLZ HELP! Need this QUICK! Thx so much! (

Mathematics
1 answer:
Semenov [28]3 years ago
5 0

Answer:

2, 5, 8

Step-by-step explanation:

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PLEASE HELP<br> 5.<br> If t= -3, then 3t^2 +5t +6 equals<br> A. -36<br> B. -6<br> c. 6 <br> D. 18
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Answer:

D

Step-by-step explanation:

substitute t=-3 in the equation

3(-3) squared +5(-3)+6=18

6 0
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This is a tricky one
IgorLugansk [536]
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What is 7.13×10 to the fifth power in standard form
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WHO RUNS THE FASTEST? HELP
Vlada [557]

Answer:

Jessica runs the fastest

Step-by-step explanation:

If you divide all of the lengths they ran by the time it took them to run in seconds, you find how much feet they run each second and Jessica ran the most feet in the least amount of time which means she runs the fastest.

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Evaluate each finite series for the specified number of terms. 1+2+4+...;n=5
zaharov [31]

Answer:

31

Step-by-step explanation:

The series are given as geometric series because these terms have common ratio and not common difference.

Our common ratio is 2 because:

1*2 = 2

2*2 = 4

The summation formula for geometric series (r ≠ 1) is:

\displaystyle \large{S_n=\frac{a_1(r^n-1)}{r-1}} or \displaystyle \large{S_n=\frac{a_1(1-r^n)}{1-r}}

You may use either one of these formulas but I’ll use the first formula.

We are also given that n = 5, meaning we are adding up 5 terms in the series, substitute n = 5 in along with r = 2 and first term = 1.

\displaystyle \large{S_5=\frac{1(2^5-1)}{2-1}}\\\displaystyle \large{S_5=\frac{2^5-1}{1}}\\\displaystyle \large{S_5=2^5-1}\\\displaystyle \large{S_5=32-1}\\\displaystyle \large{S_5=31}

Therefore, the solution is 31.

__________________________________________________________

Summary

If the sequence has common ratio then the sequence or series is classified as geometric sequence/series.

Common Ratio can be found by either multiplying terms with common ratio to get the exact next sequence which can be expressed as \displaystyle \large{a_{n-1} \cdot r = a_n} meaning “previous term times ratio = next term” or you can also get the next term to divide with previous term which can be expressed as:

\displaystyle \large{r=\frac{a_{n+1}}{a_n}}

Once knowing which sequence or series is it, apply an appropriate formula for the series. For geometric series, apply the following three formulas:

\displaystyle \large{S_n=\frac{a_1(r^n-1)}{r-1}}\\\displaystyle \large{S_n=\frac{a_1(1-r^n)}{1-r}}

Above should be applied for series that have common ratio not equal to 1.

\displaystyle \large{S_n=a_1 \cdot n}

Above should be applied for series that have common ratio exactly equal to 1.

__________________________________________________________

Topics

Sequence & Series — Geometric Series

__________________________________________________________

Others

Let me know if you have any doubts about my answer, explanation or this question through comment!

__________________________________________________________

7 0
3 years ago
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