Fill in the blanks:

Skylar needs to buy a pair of dress pants for $40, a shirt for $30, and a tie for $20. Skylar has three coupons. The first coupo

Gnom [1K]

The answer is 1-y I just did this quiz in k12 I did it today at first I didn't get it but then I do know

are you In k12 9th grade?

8 0

3 years ago

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Given y = 2(x-3) and a domain of (-3,-2 and 5). Find the range.

alexandr402 [8]

The answers are (-3,-12), (-2,-10), (5,4)

4 0

3 years ago

Waiting on the platform, a commuter hears an announcement that the train is running five minutes late. He assumes the arrival ti

natima [27]

Answer:

D. 91%

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Less than 15 minutes.

Event B: Less than 10 minutes.

We are given the following probability distribution:

$f(T = t) = \frac{3}{5}(\frac{5}{t})^4, t \geq 5$

Simplifying:

$f(T = t) = \frac{3*5^4}{5t^4} = \frac{375}{t^4}$

Probability of arriving in less than 15 minutes:

Integral of the distribution from 5 to 15. So

$P(A) = \int_{5}^{15} = \frac{375}{t^4}$

Integral of $\frac{1}{t^4} = t^{-4}$ is $\frac{t^{-3}}{-3} = -\frac{1}{3t^3}$

Then

$\int \frac{375}{t^4} dt = -\frac{125}{t^3}$

Applying the limits, by the Fundamental Theorem of Calculus:

At $t = 15$ , $f(15) = -\frac{125}{15^3} = -\frac{1}{27}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A) = -\frac{1}{27} + 1 = -\frac{1}{27} + \frac{27}{27} = \frac{26}{27}$

Probability of arriving in less than 15 minutes and less than 10 minutes.

The intersection of these events is less than 10 minutes, so:

$P(B) = \int_{5}^{10} = \frac{375}{t^4}$

We already have the integral, so just apply the limits:

At $t = 10$ , $f(10) = -\frac{125}{10^3} = -\frac{1}{8}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A \cap B) = -\frac{1}{8} + 1 = -\frac{1}{8} + \frac{8}{8} = \frac{7}{8}$

If given the train arrived in less than 15 minutes, what is the probability it arrived in less than 10 minutes?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{7}{8}}{\frac{26}{27}} = 0.9087$

Thus 90.87%, approximately 91%, and the correct answer is given by option D.

3 0

3 years ago

The perimeter of a rectangle is 50 cm and the length is 4 cm longer than the width. Write and solve the system of equations usin

k0ka [10]

P=2(l+w)
50=2(4+w)
50=8+2w
collect the like terms 50-8=2w
42=2w divide both sides by 2
w=21

6 0

4 years ago

Mika needs to equally separate 12.25 ounces of puppy food in order to feed 8 puppies the same amount. How many ounces of food wi

Reil [10]

Equation: 8p = 12.25

Ounces of food per puppy: Approximately 1.5

Mika has 12.25 ounces of puppy food to feed 8 puppies.

All 8 puppies need the same amount.

So, how many ounces of food will each puppy get?

That's where I come in.

I guess.

To find out how many ounces of food each puppy gets, you must make an equation.

Luckily for you, I've already made an equation of this in my head before I even finished typing this sentence.

You can use my equation if you want.

Equation: 8p = 12.25

Divide both sides by 8 to get approximately (hence I rounded to the nearest tenth) 1.5 ounces of food per puppy.

Now you've got some nice work to show your teacher and you've got the correct answer. Well done.

8 0

3 years ago

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