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Vesnalui [34]
2 years ago
15

PLEASE HELP I GIVE THANKS

Mathematics
1 answer:
xenn [34]2 years ago
6 0
The answer is choice C
Plane D(choice C) because choice a and b are not lines(one letter cannot be a line and PBC and not connected). It's not d because e isn't a point
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Mr and mrs. Dorsey and their three children are fling to Springfield. The cost of each ticket is $179. Estimate how much the tic
Soloha48 [4]
<span>First figure out how many people there are all together. So mrs and mr is 2 there three children so 2+3=5 so next round 179 to 200 and multiply 200x5. To do that you can use the mental math way witch would be to take the whole number out of 200 and make it 2. Then take the 5 in 200x5 and multiply 2x5. Then add the 2 zeros there were. And your estamated answer would be 1,000.
2+3=5
179=200
200x5
2x5=10
1,000
To figure out your real answer you will have to take 179 and multiply it by 5 so it will look like this:
 34
179
x
   5
895
Soto conculde the answer would be:

Estamated: $1,000

Exact: $895

Hope this helps!</span>
7 0
3 years ago
the area of triangle ABC is 28 ft squared what is the area of the parallelogram ABCD 14 ft squared 56 ft squared 112 ft squared
Kazeer [188]

Answer:

56

Step-by-step explanation:

A∆ = BH/2

Area of a parm is BH (base x height) so we multiply area of triangle by 2.

28 x 2 = 56. There you go

6 0
2 years ago
Read 2 more answers
one if the lights flickers every 7 seconds and the other light flickers very 8 seconds. how many seconds until both lights flick
bixtya [17]
It would be 56 seconds until both flicker at the same time

have a happy day :)
5 0
3 years ago
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Is k6= a solution or non solution
mrs_skeptik [129]
I think it will be a solution. Hope it help!
6 0
3 years ago
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A random sample of 100 people was taken. Eighty of the people in the sample favored Candidate A. We are interested in determinin
riadik2000 [5.3K]

Answer:

Option b - not significantly greater than 75%.

Step-by-step explanation:

A random sample of 100 people was taken i.e. n=100

Eighty of the people in the sample favored Candidate i.e. x=80

We have used single sample proportion test,

p=\frac{x}{n}

p=\frac{80}{100}

p=0.8

Now we define hypothesis,

Null hypothesis H_0 : candidate A is significantly greater than 75%.

Alternative hypothesis H_1 : candidate A is not significantly greater than 75%.

Level of significance \alpha=0.05

Applying test statistic Z -proportion,

Z=\frac{\widehat{p}-p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}

Where, \widehat{p}=80\%=0.80 and p=75%=0.75

Substitute the values,

Z=\frac{0.80-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}

Z=\frac{0.80-0.75}{\sqrt{\frac{0.1875}{100}}}

Z=\frac{0.05}{0.0433}

Z=1.1547

The p-value is

P(Z>1.1547)=1-P(Z

P(Z>1.1547)=1-0.8789

P(Z>1.1547)=0.1241

Now, the p-value is greater than the 0.05.

So we fail to reject the null hypothesis and conclude that the A is not significantly greater than 75%.

Therefore, Option b is correct.

7 0
3 years ago
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