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NISA [10]
3 years ago
13

The function C(t) = 5t 0.1t + 3.3 models the amount of a drug in a persons bloodstream over a period of time. What is a reasonab

le domain for this function?
Mathematics
2 answers:
enyata [817]3 years ago
7 0
<span>y = 50x/(x+33)
x≠-33
xy + 33y = 50x
33y = x(50-y)
33y/(50-y)= x

or y≠50

=> yϵ R - {50} </span>
Dmitry_Shevchenko [17]3 years ago
5 0

Answer:

The answer is 0 < x < ∞

Step-by-step explanation:

Since t represents the amount of time that has passed a reasonable domain is 0 < x < ∞.

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Plz help I will give brainliest
arsen [322]

Answer:

#8. M = -8/9

#9. M = 3/5

6 0
2 years ago
Use slopes and y-intercepts to determine if the lines 5x-5y=-2 and -x+2y=4
HACTEHA [7]

The given pair of lines are not perpendicular.

<h3>What is a line?</h3>

The line is a curve showing the shortest distance between 2 points.

5x - 5y = -2 - - - - - (1)
Transform the equation into standard form,
5x + 2 = 5y
y = 5x /5 + 2/5
y = x + 2/5


The slope of equation 1 is m_1 = 1  and intercept c = 2 / 5


Similarly
x + 2y = 4    - - - - - - - -(2)
Transform it into standard form
y = -x/2 + 4 /2
y = -x / 2 + 2


Slope of the equation 2  m_2= -1 / 2 and intercept c = 2
Slope of line 1 * slope of line 2 = 1 * -1/2 = -1/2


Since the lines are not perpendicular because the pair of lines does not satisfy the property of perpendicular lines i.e
m_1*m_2 = -1

Thus, the given pair of lines are not perpendicular.

Learn more about lines here:

brainly.com/question/2696693

#SPJ1  

6 0
1 year ago
What is the value of m, when 2⁶ x 4 = 418​
yaroslaw [1]

Answer:

The answer should be 3.3/4

Step-by-step explanation:

5 0
2 years ago
Mia spends 45 min reading each day. She does 2/5 of her reading at school. How many minutes does Mia spend reading at school?
Cerrena [4.2K]
Mia spends 18 minutes reading at school.
3 0
3 years ago
Read 2 more answers
Write an equation of the line using the given information:
grigory [225]
Y - y1 = m(x - x1)
slope(m) = 2/5
(6,2)....x1 = 6 and y1 = 2
now we sub
y - 2 = 2/5(x - 6)
7 0
3 years ago
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