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Klio2033 [76]
3 years ago
10

%7D%20%2B%2030%29%20" id="TexFormula1" title=" {40a}^{2} + 20a - 30 = ( - 1)( {15a}^{3} + 30) " alt=" {40a}^{2} + 20a - 30 = ( - 1)( {15a}^{3} + 30) " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
KonstantinChe [14]3 years ago
7 0

\bf 40a^2+20a-30=(-1)(15a^3+30)\implies 40a^2+20a~~\begin{matrix} -30 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~=-15a^3~~\begin{matrix} -30 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} \\\\\\ 40a^2+20a=-15a^3\implies 15a^3+40a^2+20a=0\implies 5a(3a^2+8a+4)=0 \\\\\\ 5a(3a+2)(a+2)=0\implies a= \begin{cases} 0\\ -\frac{2}{3}\\ -2 \end{cases}

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Answer:

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Nat2105 [25]
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2 years ago
Find a linear inequality with the following solution set. Each grid line represents one unit. [asy] size(200); fill((-2,-5)--(5,
kykrilka [37]

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<h3>How to determine the linear inequality?</h3>

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Learn more about linear inequality at:

brainly.com/question/19491153

#SPJ1

<u>Complete question</u>

Find a linear inequality with the following solution set. Each grid line represents one unit. (Give your answer in the form ax+by+c>0 or ax+by+c \geq 0 where a, b, and c are integers with no common factor greater than 1.)

4 0
2 years ago
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