Answer:
Hence, option: B is correct (11.02 seconds)
Step-by-step explanation:
Spencer hits a tennis ball past his opponent. The height of the tennis ball, in feet, is modeled by the equation h(t) = –0.075t2 + 0.6t + 2.5, where t is the time since the tennis ball was hit, measured in seconds.
Now we are asked:
How long does it take for the ball to reach the ground?
i.e. we have to find the value of t such that height is zero i.e. h(t)=0.

or 
i.e. we need to find the roots of the above quadratic equation.
on solving the equation we get two roots as:
t≈ -3.02377 and t≈11.0238
As time can't be negative; hence we will consider the value of t as t≈11.0238.
Hence it takes 11.02 seconds for the ball to reach the ground.
Hence option B is correct (11.02 seconds).
Answer:
A. The y-intercept of g(x) is less than the y-intercept of f(x).
Step-by-step explanation:
The x-intercept, or when x = 0, of f(x) is -4, the x-intercept of g(x) is -8, so g(x) are neither greater nor equal to f(x), this marks out C and D. The y-intercept, or when y = 0, is in this case f(x) or g(x). The y-intercept of f(x) is 16, the y-intercept of g(x) is 4, so the y-intercept of g(x) is not equal to the y-intercept of f(x), this marks out B. Now to check A, 4 < 16, so y-intercept of g(x) < y-intercept of f(x), the answer is A
9514 1404 393
Answer:
1/8
Step-by-step explanation:
The fraction of the total is ...
(1/6) of (3/4) = (1×3)/(6×4) = 3/24 = 1/8
1/8 of the total garden is carrots.
Answer: 6x
Work Shown:
For each step, the logs are all base b. This is to save time and hassle of writing tricky notation of having to write the smaller subscript 'b' multiple times. The first rule to use is that log(x^y) = y*log(x) for any base of a logarithm. The second rule is that
meaning that the log base of itself is 1
log(b^(6x)) = 6x*log(b) .... pull down exponent using the first rule above
log(b^(6x)) = 6x*1 .... use the second rule mentioned
log(b^(6x)) = 6x
Answer:
The minimum IQ score will be "126".
Step-by-step explanation:
The given values are:
Mean

Standard deviation

Now,
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⇒ 
⇒ 
⇒ 


⇒ 
