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Shtirlitz [24]
3 years ago
5

What is the hexadecimal and decimal equivalent of the binary number 110010001110

Computers and Technology
1 answer:
arlik [135]3 years ago
6 0

<span><em>Hexadecimal:</em>
</span>1100 1000 1110
1100 = C
1000 = 8
1110 = E


Hexadecimal: C8E


<span><em>Decimal:</em>
</span>1100 1000 1110
<span>= 2^1^1, 2^1^0, 2^9, 2^8, 2^7, 2^6, 2^5, 2^4, 2^3, 2^2, 2^1, 2^0
<em>= </em>2048, 1024, 512, 256, 128, 64, 32, 16, 8, 4, 2, 1
<em>Multiply each value with it's corresponding binary digit (eg: 2048x1, 1024x1, 512x0, etc.) then add them all together.
</em>= 2048+1024+0+0+128+0+0+0+8+4+2+0</span>

<span>
</span>

<span>Binary: 3214</span>

<span />


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#Starting point for code/programm

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lb $t3,($t1) # Load the starting address of input word

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jal convert2lower

move $t2,$v0 # Store the return($v0) value into $t2

move $a0,$t3 # Convert $t3 to lower, if it is upper case

jal convert2lower

move $t3,$v0 # Store the return($v0) value into $t3

bne $t2,$t3,next_char1 # If both characters are not matched current

# character in the string, go to next character

addiu $t0,$t0,1 # otherwise, increment both indexes

addiu $t1,$t1,1

j loop1 # go to starting of the loop

next_char1:

la $t5,fword

bne $t5,$t1,nstart1

la $t1,fword # Store the input word into $t1

addiu $t0,$t0,1 # Increment the index to goto next character

j loop1 # go to starting of the loop

inc_counter1:

addi $t4,$t4,1 # Increment the frequency counter by 1

la $t1,fword # Store input word into $t1

j loop1 # go to starting of the loop

print_output1:

la $t0,fword

L1:

lb $a0,($t0)

beq $a0,'\n',exL1

jal convert2upper

move $a0,$v0

li $v0,11

syscall

addiu $t0,$t0,1

j L1

exL1:

la $a0,colon

li $v0,4

syscall

la $a0, dash

li $v0, 4

syscall

move $a0,$t4

li $v0,1

syscall # print new line

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li $v0,4

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# of input word in the given statment

lb $t2,($t0) # Load the starting address(character) of

# sstatement into $t2

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# into $t3

beq $t3,'\n',inc_counter2

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move $a0,$t2 # Convert $t2 to lower, if it is upper case

jal convert2lower

move $t2,$v0 # Store the return($v0) value into $t2

move $a0,$t3 # Convert $t3 to lower, if it is upper case

jal convert2lower

move $t3,$v0 # Store the return($v0) value into $t3

bne $t2,$t3,next_char2 # If both characters are not matched current

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la $t5,sword

bne $t5,$t1,nstart2

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addi $t4,$t4,1 # Increment the frequency counter by 1

la $t1,sword # Store input word into $t1

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la $t0,sword

L2:

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move $a0,$v0

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############################## subroutine - convert2upper ##################################

convert2upper: # Converts a character(stored in $a0) to

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addiu $v0,$a0,-32

return2: jr $ra # Return the converted(lower case) character

4 0
3 years ago
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