Answer:
A. 0.2222
B. Repeat indefinitely
Step-by-step explanation:
A. We have that Scott has 9 pieces in total and he eats 2 of them. That means he eats 2 <em>out of </em>the 9, so we have 2 ÷ 9. (see attachment)
The decimal form is: 0.2222.
B. Clearly, we can see that throughout the long division, we keep getting 20 - 18 = 2, which makes another 20 and so on. So, this will repeat indefinitely.
Answer:
Step-by-step explanation:
(ab + bc)(ab + bc)
Simplifying
(ab + bc)(ab + bc)
Multiply (ab + bc) * (ab + bc)
(ab(ab + bc) + bc(ab + bc))
((ab * ab + bc * ab) + bc(ab + bc))
Reorder the terms:
((ab2c + a2b2) + bc(ab + bc))
((ab2c + a2b2) + bc(ab + bc))
(ab2c + a2b2 + (ab * bc + bc * bc))
(ab2c + a2b2 + (ab2c + b2c2))
Reorder the terms:
(ab2c + ab2c + a2b2 + b2c2)
Combine like terms: ab2c + ab2c = 2ab2c
(2ab2c + a2b2 + b2c2)
Answer:
(1, -3) can be removed so that the resulting graph represents a function. A relation from a set X to a set Y is called a function if each element of X is related to exactly one element in Y
Step-by-step explanation:
Answer:
37.68 cm
Step-by-step explanation:
The formula for circumference is C= 2* (3.14) r
First you can actually cut 12 by 1/2
12 * 1/2 is 6. This works because 12 is an even number.
2 * 3.14 (6) gives you 37.68 cm.
So i believe the answer is 37.68 cm.
Substitute

, so that

![\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1x\dfrac{\mathrm dy}{\mathrm dz}\right]=-\dfrac1{x^2}\dfrac{\mathrm dy}{\mathrm dz}+\dfrac1x\left(\dfrac1x\dfrac{\mathrm d^2y}{\mathrm dz^2}\right)=\dfrac1{x^2}\left(\dfrac{\mathrm d^2y}{\mathrm dz^2}-\dfrac{\mathrm dy}{\mathrm dz}\right)](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%5E2y%7D%7B%5Cmathrm%20dx%5E2%7D%3D%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cleft%5B%5Cdfrac1x%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dz%7D%5Cright%5D%3D-%5Cdfrac1%7Bx%5E2%7D%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dz%7D%2B%5Cdfrac1x%5Cleft%28%5Cdfrac1x%5Cdfrac%7B%5Cmathrm%20d%5E2y%7D%7B%5Cmathrm%20dz%5E2%7D%5Cright%29%3D%5Cdfrac1%7Bx%5E2%7D%5Cleft%28%5Cdfrac%7B%5Cmathrm%20d%5E2y%7D%7B%5Cmathrm%20dz%5E2%7D-%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dz%7D%5Cright%29)
Then the ODE becomes


which has the characteristic equation

with roots at

. This means the characteristic solution for

is

and in terms of

, this is

From the given initial conditions, we find


so the particular solution to the IVP is