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makvit [3.9K]
3 years ago
15

Kim is a single woman in her mid-20s working while taking college credits to earn a bachelors degree. She is financing her educa

tion herself through both her income and taking out student loans. Her earnings in 2010 were $30,000 before taxes. She paid $5000 intuition and paid $350 interest on her student loan. In filing her state tax return form Kim takes a deduction for tuition paid and the interest paid on the loan. In taking these two deductions by how much did she lower taxable income? What is her taxable income now? What is her marginal tax rate? What will she owe in taxes for 2010?

Mathematics
1 answer:
alexandr1967 [171]3 years ago
7 0
Previous taxable income - 30,000
Less: Deductions - 5,000 + 350 = 5,350
New taxable income - 24,650
Multiply: Marginal tax rate - 15%
Tax - 3,697.50

1.) She lowered her taxable income by 5,350.
2.) Her taxable income now is 24,650.
3.) Her taxable income falls under the income range of 8,375 - 34,000, so her marginal tax rate is 15%.
4.) She will have to pay 3,697.50 for her tax.
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Find the roots of the equation f(x) = x3 - 0.2589x2 + 0.02262x -0.001122 = 0
devlian [24]

Answer:

The root of the equation x^3-0.2589x^{2}+0.02262x-0.001122=0 is x ≈ 0.162035

Step-by-step explanation:

To find the roots of the equation x^3-0.2589x^{2}+0.02262x-0.001122=0 you can use the Newton-Raphson method.

It is a way to find a good approximation for the root of a real-valued function f(x) = 0. The method starts with a function f(x) defined over the real numbers, the function derivative f', and an initial guess x_{0} for a root of the function. It uses the idea that a continuous and differentiable function can be approximated by a straight line tangent to it.

This is the expression that we need to use

x_{n+1}=x_{n} -\frac{f(x_{n})}{f(x_{n})'}

For the information given:

f(x) = x^3-0.2589x^{2}+0.02262x-0.001122=0\\f(x)'=3x^2-0.5178x+0.02262

For the initial value x_{0} you can choose x_{0}=0 although you can choose any value that you want.

So for approximation x_{1}

x_{1}=x_{0}-\frac{f(x_{0})}{f(x_{0})'} \\x_{1}=0-\frac{0^3-0.2589\cdot0^2+0.02262\cdot 0-0.001122}{3\cdot 0^2-0.5178\cdot 0+0.02262} \\x_{1}=0.0496021

Next, with x_{1}=0.0496021 you put it into the equation

f(0.0496021)=(0.0496021)^3-0.2589\cdot (0.0496021)^2+0.02262\cdot 0.0496021-0.001122 = -0.0005150, you can see that this value is close to 0 but we need to refine our solution.

For approximation x_{2}

x_{2}=x_{1}-\frac{f(x_{1})}{f(x_{1})'} \\x_{1}=0-\frac{0.0496021^3-0.2589\cdot 0.0496021^2+0.02262\cdot 0.0496021-0.001122}{3\cdot 0.0496021^2-0.5178\cdot 0.0496021+0.02262} \\x_{1}=0.168883

Again we put x_{2}=0.168883 into the equation

f(0.168883)=(0.168883)^3-0.2589\cdot (0.168883)^2+0.02262\cdot 0.168883-0.001122=0.0001307 this value is close to 0 but again we need to refine our solution.

We can summarize this process in the following table.

The approximation x_{5} gives you the root of the equation.

When you plot the equation you find that only have one real root and is approximate to the value found.

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3 years ago
Rick buys remote control cars to resell. He applies a markup of 21%. Enter two expressions that represent the retail price of th
11111nata11111 [884]

The two expressions that represent the retail price of cars is: Retail price = 1.21c and Retail price = c + 0.21c

<em><u>Solution:</u></em>

Given that,

Rick buys remote control cars to resell

He applies a markup of 21%

Let "c" be the original price of remote control cars

To find: Expression for retail price of car

We know that,

Retail price = original price + markup

Here, markup price = 21 % of original price

Markup price = 21 % of c

Therefore, substituting the given values we get,

Retail price = c + 21 % of c

\text{ Retail price } = c + 21 \% \times c\\\\\text{ Retail price } = c + \frac{21}{100} \times c\\\\\text{ Retail price } = c + 0.21c\\\\

This can also be expressed as,

\text{ Retail price } = c + 0.21c = 1.21c

Thus two expressions that represent the retail price of cars is: Retail price = 1.21c and Retail price = c + 0.21c

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2 Percent or %

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