Answer:
I Don't Know if this is right, but for the first part it would be people making hype for a product so more people know about it.
Sorry thats all I got, but i saw u had no other answers so I hope this did You some good :(
It’s either presentation Because the software is used to create a sequence of texting, graphics and often audio and video to accompany a speech or a public presentation, or letter
Answer:
3. ReFS
Explanation:
Only in ReFS include and others do not have all of the below features
1. Automatic integrity checking and data scrubbing
2. Removal of the need for running chkdsk
3. Protection against data degradation
4. Built-in handling of hard disk drive failure and redundancy
5. Integration of RAID functionality
6. A switch to copy/allocate on write for data and metadata updates
7. Handling of very long paths and filenames
8. Storage virtualization and pooling
Answer:
Since the question expect us to declare a C-string, the solution code is written in C as follows:
- char ssn[9];
- scanf("%s",ssn);
Explanation:
A C-String is a string written in C language. It is an array of characters. To declare a C-string, we use the keyword, <em>char </em>and then followed with the variable name + brackets and the number of characters in the string. For example, we can create a C-String for the SSN number as in Line 1.
To read standard input into the array, we can use C built-in function, <em>scanf(). </em>Just include a string placeholder, %s, and the variable<em> ssn </em>as arguments to <em>scanf()</em>. This will assign the string input by user to variable <em>ssn</em> as C-String.
Answer:
Check the explanation
Explanation:
CPI means Clock cycle per Instruction
given Clock rate 600 MHz then clock time is Cー 1.67nSec clockrate 600M
Execution time is given by following Formula.
Execution Time(CPU time) = CPI*Instruction Count * clock time = 
a)
for system A CPU time is 1.3 * 100, 000 600 106
= 216.67 micro sec.
b)
for system B CPU time is 
= 333.33 micro sec
c) Since the system B is slower than system A, So the system A executes the given program in less time
Hence take CPU execution time of system B as CPU time of System A.
therefore
216.67 micro = =
Instructions = 216.67*750/2.5
= 65001
hence 65001 instruction are needed for executing program By system B. to complete the program as fast as system A
