Answer:
Step-by-step explanation:
Given
The attached piece wise function
Required
The domain
To do this, we simply consider the inequalities that bound the values of x.
The inequalities are:
and
Combine the first two inequalities:
and
For the inequality to be true, we must have:
In interval notation, the inequality is:
Answer:
x = ± 1 , x = ±
Step-by-step explanation:
Let u = x² , then
- 3x² + 2 = 0 , can be expressed as
u² - 3u + 2 = 0 ← in standard form
(u - 1)(u - 2) = 0 ← in factored form
Equate each factor to zero and solve for u
u - 1 = 0 ⇒ u = 1
u - 2 = 0 ⇒ u = 2
Change the variable u back to x
x² = 1 ( take square root of both sides )
x = ± 1
or
x² = 2 ( take square root of both sides )
x = ±