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const2013 [10]
3 years ago
8

stephen is making curtains for several windows in his aunt's house. he determines that he needs 8.5 yards of fabric for each win

dow. write an equation to represent the number of yards of fabric needed given a certain number of windows
Mathematics
1 answer:
pashok25 [27]3 years ago
8 0

Answer:

F(n) = 8.5*n yards, where n is the number of windows

Step-by-step explanation:

Suppose the house of Stephen's aunt has n windows.

Since he needs 8.5 yards of fabric for each window, then he needs 8.5 times n yards of fabric for the n windows.

Call F(n) the yards of fabric he needs for the n windows, then

F(n) = 8.5*n

For example, if auntie's house had 4 windows, then

F(4) = 8.5*4 = 34 yards.

If auntie's house had 6 windows

F(6) = 51 yards.

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Genrish500 [490]

Answer:

5.66 units.

Step-by-step explanation:

cos 25 =- adjacent side / hypotenuse

cos 25 = 4 / AB

AB  cos 45 = 4

AB = 4 / cos 45

= 5.66.

3 0
3 years ago
maggie's brother is 3 years younger than twice her age. the sum of their ages is 24. write solve an equation to determine maggie
prohojiy [21]
Maggie =x
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7 0
3 years ago
ATA movie theater the size of popcorn has decreased by 10%. If the old bag held 14 cups how much does the new bag hold
Burka [1]

I think

Step-by-step explanation:

12.5 since it decreases 10% and the old bag had 14 cups and 10% is 1.4

3 0
3 years ago
Can you create a triangle with one obtuse angle and one right angle? Why or why not?
valina [46]
An obtuse triangle (or obtuse-angled triangle) is a triangle with one obtuse angle (greater than 90°) and two acute angles. ... Since a triangle's angles must sum to 180° in Euclidean geometry, no Euclidean triangle can have more than one obtuse angle.
8 0
3 years ago
This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex
harina [27]
L(x,y,z,\lambda)=8x+8y+4z+\lambda(4x^2+4y^2+4z^2-36)

L_x=8+8\lambda x=0\implies 1+\lambda x=0
L_y=8+8\lambda y=0\implies 1+\lambda y=0
L_z=4+8\lambda z=0\implies 1+2\lambda z=0
L_\lambda=4x^2+4y^2+4z^2-36=0\implies x^2+y^2+z^2=9

yL_x=y+\lambda xy=0
xL_y=x+\lambda xy=0
\implies yL_x-xL_y=y-x=0\implies y=x

2zL_x=2z+2\lambda xz=0
xL_z=x+2\lambda xz=0
\implies 2zL_x-xL_z=2z-x=0\implies x=2z

2zL_y=2z+2\lambda yz=0
yL_z=y+2\lambda yz=0
\implies 2zL_y-yL_z=2z-y=0\implies y=2z

x=y=2z\implies x^2+y^2+z^2=9\iff 4z^2+4z^2+z^2=9z^2=9\implies z=\pm1

z=\pm1\implies y=x=\pm2

So we have two critical points, (2, 2, 1) and (-2, -2, -1), which respectively give a max of 36 and a min of -36.
5 0
3 years ago
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