Answer: -3
please please mark as brainliest
Answer:
We are given the below probability distribution table:
x P(x)
100 0.180
200 0.051
300 0.227
400 0.113
500 0.090
600 0.099
700 0.165
800 0.075
Now to find the mean, we have to use the below formula:
![Mean, \mu=\sum xP(x)](https://tex.z-dn.net/?f=Mean%2C%20%5Cmu%3D%5Csum%20xP%28x%29)
![=(100 \times 0.180)+(200 \times 0.051)+(300 \times 0.227)+(400 \times 0.113)+(500 \times 0.090)+(600 \times 0.099)+(700 \times 0.165)+(800 \times 0.075)](https://tex.z-dn.net/?f=%3D%28100%20%5Ctimes%200.180%29%2B%28200%20%5Ctimes%200.051%29%2B%28300%20%5Ctimes%200.227%29%2B%28400%20%5Ctimes%200.113%29%2B%28500%20%5Ctimes%200.090%29%2B%28600%20%5Ctimes%200.099%29%2B%28700%20%5Ctimes%200.165%29%2B%28800%20%5Ctimes%200.075%29)
![=18+10.2+68.1+45.2+45+59.4+115.5+60](https://tex.z-dn.net/?f=%3D18%2B10.2%2B68.1%2B45.2%2B45%2B59.4%2B115.5%2B60)
![=421.4](https://tex.z-dn.net/?f=%3D421.4)
Therefore, the mean is
Answer:
x=3
Step-by-step explanation:
the volume of the prism with triangular base is 54 unit³
The base is a triangle with, base i.e 4 units and height i.e x units
Also, height of the prism = 3x
So, volume of the prism is,
And
,
![Area_{Triangle}=\dfrac{1}{2}\times base\times Height_{Triangle}=\dfrac{1}{2}\times 4\times x=2x\ unit^2](https://tex.z-dn.net/?f=Area_%7BTriangle%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20base%5Ctimes%20Height_%7BTriangle%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%204%5Ctimes%20x%3D2x%5C%20unit%5E2)
Then,
![V_{Prism}=2x\times 3x=6x^2](https://tex.z-dn.net/?f=V_%7BPrism%7D%3D2x%5Ctimes%203x%3D6x%5E2)
As the volume is given as 54 unit³, hence
6x²=54
x²=9
x=3
Answer: z-1 (6) = 0
Step-by-step explanation:
I suppose that the notation:
(z-1)(x) refers to the inverse function of z(x).
Now, by definition, we know that:
if z(x) = y
then z-1(y) = x.
Now we want to find the value of z-1(6)
This value will be equal to the input that we need have:
z(x) = 6.
By looking at the graph, we can see that the value of the function is 6 when x = 0.
then:
z (0) = 6
This implies that:
z-1 (6) = 0