Question

In the following chemical equation, the atomic inventory for which element has been done incorrectly? 2KClO3 2KCl + 3O2 reactant elements atomic inventory product elements atomic inventory potassium 1 × 2 = 2 potassium 1 × 2 = 2 chlorine 3 × 2 = 6 chlorine 1 × 2 = 2 oxygen 3 × 2 = 6 oxygen 2 x 3 = 6 potassium chlorine oxygen more than one element

Answer 1

Answer:

On both the side chlorine atoms will be present in equal numbers

Step-by-step explanation:

$2KClO_3\rightarrow 2KCl+3O_2$

Number of atoms on left hand side:

Potassium atoms, K = 2 × 1 = 2

Chlorine atoms, Cl = 2 × 1 = 2

Oxygen atom, O= 2 × 3 =6

Number of atoms on right hand side:

Potassium atoms, K = 2 × 1 = 2

Chlorine atoms, Cl = 2 × 1 = 2

Oxygen atom, O= 3 × 2 =6

From the atomic inventory , number of chlorine atoms on both the sides are equal as per as Law of Conservation of mass.

Answer 2

Chlorine, on the keft side, the chlorine equals 6 on the right only 2