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garri49 [273]
3 years ago
9

Is 10/9 closest to 0, 1/2 or 1? Explain

Mathematics
2 answers:
Elina [12.6K]3 years ago
6 0
10/9 = 1.01  and you know 1/2 = 0.5 so 1.1 is closest to 1 because there is just 0.1 different between them :))
i hope this be helpful
have a nice day 
olganol [36]3 years ago
4 0
1 is closer to 0 because it's next to it
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Find the sum of the exterior angles, one at each vertex, of a heptagon​
Vesnalui [34]
Since the sum of the exterior angles of any polygon is going to always be 360 u can take 360 and divide that by the number of sides which is 7. This gives u 51.4 degrees rounded to the nearest tenth for each exterior angle. PS. Roblox Rocks
8 0
4 years ago
Rachel and David were shopping for holiday gifts when they noticed a Thanksgiving sweater on the discount rack. Rachel really wa
Leona [35]

Answer:

Sales\ Price = \$9.60

Step-by-step explanation:

Given

Price = \$24.00

Discount = 60\%

Required

Determine the sales price

First, we calculate the discount price

Discount\ Price = Price * Discount

Discount\ Price = \$24.00 * 60\%

Discount\ Price = \$14.4

The sales price is then calculated by subtracting the discount price from the original price of the item

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8 0
3 years ago
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Over [174]
You deposit $350 in savings account. The account earns 2.5 simple.
7 0
3 years ago
Read 2 more answers
Help please!!
yanalaym [24]

Answer:  (1,-1)

Step-by-step explanation:

Midpoint of BC=(6+4)/2, (3–1)/2. =(5,1)

Slope of BC is (3+1)/4–6)= 4/-2 = -2

Slope of perpendicular bisector of BC =+1/2

Eqn of perpendicular bisector is : Y-1 =1/2 (x-5)

Y=1/2 •(x-5) +1

Midpoint of AB. (6–2)/2, (3–1)/2 ={2,1)

Slope of AB is(3+1)/(-2–6) = 4/-8 =-1/2

Slope of perpendicular bisector = +2

Eqn of perpendicular bisector is Y-1. =2( X-2)

Y=2X-4+1 = 2X -3

Solving Y=(X-5)/2 +1

& Y=2X-3

2X-3 =(x-5/2)+1

2X-4 =(x-5/2)

4X-8 = x-5

3X =3

X=1

Y= 2×1–3= -1

Circumcentre is(1,-1)

8 0
3 years ago
5 x the sum of a number and 2 is less than the number x 8. Find the number
telo118 [61]

The solution to inequality is not a number but an interval.

5(x+2) < 8x \\5x+10 < 8x \\10 < 3x \\10/3 < x \\x > 10/3\Longrightarrow x\in(10/3, +\infty)

Hope this helps.

4 0
4 years ago
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