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3 years ago

Regina's teacher recently gave her a homework assignment on solving equations. Since she has been ti

Mathematics

2 answers:

Thepotemich [5.8K]3 years ago

6 0

Answe

Step-by-step explanation:

need brainest pls

alexgriva [62]3 years ago

4 0

Answer:

what a questio.

Step-by-step explanation:what a qestion

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(6x^3 + 4x^2 + 2x) ÷ 2x Answer fast plz..

Phoenix [80]

refer to the attachment okay

mark me a brainlist answer I need only 1

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3 years ago

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he Mitchell family is renting a boat for the day. The boat rental has a flat fee of $100 plus $20 for each hour. They have to pa

valentinak56 [21]

250-100 = 150

150/20 = 7.5

7 hours

inequality: 100+20x <=250

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4 years ago

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HELP ME can't figure this out. Please help

malfutka [58]

Answer:

The answer to your question is: letter J is the right answer

Step-by-step explanation:

3x - 4y = 6

Solve for y

Add - 3x in both sides 3x - 3x - 4y = -3x + 6

Simplify -4y = -3x + 6

Divide by -4 -4/-4 y = -3/-4 x + 6/-4

Simplify y = 3/4x - 6/4

y = 3/4 x - 3/2

3 0

3 years ago

Use logarithmic differentiation to find dy/dx: y=((x^3)(2x+3)^1/2) / (x-2)^2

sukhopar [10]

$y=\frac { { { x }^{ 3 }\left( 2x+3 \right) }^{ \frac { 1 }{ 2 } } }{ { \left( x-2 \right) }^{ 2 } }$

$\\ \\ { \left( x-2 \right) }^{ 2 }\cdot y={ x }^{ 3 }{ \left( 2x+3 \right) }^{ \frac { 1 }{ 2 } }$

$\\ \\ \ln { \left( { \left( x-2 \right) }^{ 2 }\cdot y \right) } =\ln { \left( { x }^{ 3 }{ \left( 2x+3 \right) }^{ \frac { 1 }{ 2 } } \right) }$

$\\ \\ \ln { \left( { \left( x-2 \right) }^{ 2 } \right) } +\ln { y } =\ln { \left( { x }^{ 3 } \right) } +\ln { \left( { \left( 2x+3 \right) }^{ \frac { 1 }{ 2 } } \right) }$

$\\ \\ 2\ln { \left( x-2 \right) } +\ln { y } =3\ln { x } +\frac { 1 }{ 2 } \ln { \left( 2x+3 \right) }$

$\\ \\ \ln { y } =3\ln { x } -2\ln { \left( x-2 \right) } +\frac { 1 }{ 2 } \ln { \left( 2x+3 \right) }$

$\\ \\ \frac { 1 }{ y } \cdot \frac { dy }{ dx } =\frac { 3 }{ x } -\frac { 2 }{ x-2 } +\frac { 1 }{ 2x+3 }$

$\\ \\ y\cdot \frac { 1 }{ y } \cdot \frac { dy }{ dx } =y\left( \frac { 3 }{ x } -\frac { 2 }{ x-2 } +\frac { 1 }{ 2x+3 } \right)$

$\\ \\ \frac { dy }{ dx } =\frac { { x }^{ 3 }\sqrt { 2x+3 } }{ { \left( x-2 \right) }^{ 2 } } \cdot \left( \frac { 3 }{ x } -\frac { 2 }{ x-2 } +\frac { 1 }{ 2x+3 } \right)$

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3 years ago

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Evaluate the function f(x)=-3x+7 a) find f(2) b)find f(-6)

yuradex [85]

F(2)= -3(2)+7= -6+7= 1

f(6)= -3(6)+7= -18+7= -11

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3 years ago