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Colt1911 [192]
3 years ago
14

Teenagers spend billions of dollars on stereo equipment and compact discs. they have the ability, willingness, and authority to

purchase such products because of their perceived need. these teenagers are an example of a(n) ____ market.
a. governmental
b. consumer
c. institutional
d. producer
e. business-to-business
Business
1 answer:
oee [108]3 years ago
5 0
Consumers market. this is because teenagers don't NEED stereo equipment to live
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Choose the correct way to complete the sentences to explain how to draw concentric circles when doing a freehand sketch.
taurus [48]

1st one is "extended tripod grip" and second one is "rotating the paper with your free hand and pulling it towards your body".

4 0
3 years ago
Conductors are assigned a ? ampacity that reflects the insulation's ability to handle and dissipate heat under ? conditions.
givi [52]

Answer:

Specific; Varying

Explanation:

Conductors are assigned a <u>specific</u> ampacity that reflects the insulations ability to handle and dissipate heat under <u>varying</u> conditions. As the ampacity concerning a conductor is based on those physical as well as electrical properties of the element as well as the formulation of the conductor including its ambient temperature, insulation, and environmental conditions proximate toward the conductor as well.

6 0
3 years ago
7) You put 20% down on a home with a purchase price of $250,000. The down payment is thus $50,000, leaving a balance owed of $20
Alexxandr [17]

Answer:

=$11,439.96(Approx)

Explanation:

Consider the following calculations

Present value of annuity=Annuity[1-(1+interest rate)^-time period]/rate

200,000=Annuity[1-(1.0391)^-30]/0.0391

200,000=Annuity*17.48257135

Annuity=200,000/17.48257135

=$11,439.96(Approx)

4 0
3 years ago
You are interested in valuing a 2-year semi-annual corporate coupon bond using spot rates but there are no liquid strips availab
Scorpion4ik [409]

Answer:

Following are the solution to this question:

Explanation:

Assume that r_1  will be a 12-month for the spot rate:

\to 1.25 \% \times \frac{100}{2} \times 0.99 + \frac{(1.25\% \times \frac{100}{2}+100)}{(1+\frac{r_1}{2})^2}=98\\\\\to \frac{1.25}{100} \times \frac{100}{2} \times 0.99 + \frac{(\frac{1.25}{100} \times \frac{100}{2}+100)}{(1+\frac{r_1}{2})^2}=98\\\\\to \frac{1.25}{2} \times 0.99 + \frac{(\frac{1.25}{2} +100)}{(1+\frac{r_1}{2})^2}=98\\\\\to 0.61875 + \frac{( 0.625 +100)}{(\frac{2+r_1}{2})^2}=98\\\\\to 0.61875 + \frac{( 100.625)}{(\frac{2+r_1}{2})^2}=98\\\\\to 0.61875 + \frac{402.5}{(2+r_1)^2}=98\\\\

\to 0.61875 + \frac{402.5}{(2+r_1)^2}=98\\\\\to 0.61875 -98 = \frac{402.5}{(2+r_1)^2}\\\\\to -97.38125= \frac{402.5}{(2+r_1)^2}\\\\\to (2+r_1)^2= \frac{402.5}{ -97.38125}\\\\\to (2+r_1)^2= -4.13\\\\ \to r_1=3.304\%

Assume that r_2  will be a 18-month for the spot rate:

\to 1.5\% \times \frac{100}{2} \times 0.99+1.5\%  \times \frac{100}{2} \times \frac{1}{(1+ \frac{3.300\%}{2})^2}+\frac{(1.5\%  \times  \frac{100}{2}+100)}{(1+\frac{r_2}{2})^3}=97\\\\\to \frac{1.5}{100} \times \frac{100}{2} \times 0.99+\frac{1.5}{100}  \times \frac{100}{2} \times \frac{1}{(1+ \frac{\frac{3.300}{100}}{2})^2}+\frac{(\frac{1.5}{100}  \times  \frac{100}{2}+100)}{(1+\frac{r_2}{2})^3}=97\\\\

\to \frac{1.5}{2}  \times 0.99+\frac{1.5}{2}\times \frac{1}{(1+ \frac{\frac{3.300}{100}}{2})^2}+\frac{(\frac{1.5}{2} +100)}{(1+\frac{r_2}{2})^3}=97\\\\\to 0.7425+0.75 \times \frac{1}{(1+ \frac{\frac{3.300}{100}}{2})^2}+\frac{(0.75  +100)}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4925 \times \frac{1}{(1+0.0165)^2}+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4925 \times \frac{1}{(1.033)}+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\

\to 1.4925 \times 0.96+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4328+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4328-97= \frac{(100.75 )}{(1+\frac{r_2}{2})^3}\\\\\to -95.5672= \frac{(100.75 )}{(1+\frac{r_2}{2})^3}\\\\\to (1+\frac{r_2}{2})^3= -1.054\\\\\to r_2=3.577\%

Assume that r_3  will be a 18-month for the spot rate:

\to 1.25\% \times \frac{100}{2} \times 0.99+1.25\% \times \frac{100}{2} \times \frac{1}{(1+\frac{3.300\%}{2})^2}+1.25\%\times\frac{100}{2} \times \frac{1}{(1+\frac{3.577\%}{2})^3}+(1.25\% \times \frac{\frac{100}{2}+100}{(1+\frac{r_3}{2})^4})=96\\\\

to solve this we get r_3=3.335\%

4 0
3 years ago
A company started a new product, and in the first month started 100,000100,000 units. The ending work in process inventory was 2
sukhopar [10]

Answer:

$240,000

Explanation:

Calculation for What is the value of the inventory transferred out, using the weighted-average inventory method

First step is to calculate the Equivalent material cost=

Equivalent material cost= 20,000×100%×$6

Equivalent material cost= 120,000

Second step is to calculate Equivalent conversion cost

Equivalent conversion cost=20,000×75%×8

Equivalent conversion cost=120,000

Now let calculate the value of the inventory transferred out, using the weighted-average inventory method

Inventory value transferred out= 120,000+120,000

Inventory value transferred out=$240,000

Therefore the value of the inventory transferred out, using the weighted-average inventory method is $240,000

4 0
3 years ago
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