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GenaCL600 [577]
3 years ago
13

Simplify.

Mathematics
1 answer:
Keith_Richards [23]3 years ago
4 0
So I am assuming that 2m2 means 2m^2 so
we can only combine m's with m's and n's with n's
group them together (m's with m's and n's with n's)
using the propoerty that says
a+b=b+a so we can move them around so


2m^2+3m-6m^2-2m-4n^2+7n^2
we can combine m^2 and m^2's but not m^2 and m so
regroup with like powers
2m^2-6m^2+3m-2m-4n^2+7n^2
add
-4m^2+m+3n^2
order in hightest power first
-4m^2+3n^2+m
the answer is A
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Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different
N76 [4]

Answer:

(a)  As time increases, the amount of water in the pool increases.

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(b)  65 gallons

Step-by-step explanation:

From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.

We are told that Ann adds water at a constant rate.  Therefore, this can be modeled as a linear function.  

The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).

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\textsf{let}\:(x_1,y_1)=(8, 153)

\textsf{let}\:(x_2,y_2)=(12,197)

Input these into the slope formula:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11

Therefore, the rate at which the water in the pool is increasing is:

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To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

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When Ann had added no water, x = 0.  Therefore,

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So there was <u>65 gallons</u> of water in the pool before Ann starting adding water.

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