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Lera25 [3.4K]
3 years ago
14

Find the missing angle measure.

Mathematics
1 answer:
ycow [4]3 years ago
5 0

Step-by-step explanation:

The sum of all inner angles in the shape should be 540°

(180° for triangles, 360° for squares and other simple 4-corner-shapes, the pattern is the number of corners minus 2 multiplied by 180°)

we can calculate

540-106-94-135=205

so we got 205 degrees for the two unclear corners and one of them has to be 5° greater.

x is 100°

x is 100°x+5 is 105°

(note that in the subtraction part we could have subtracted 5 more and would be left with 2x=200)

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How many bucketloads would it take to bucket out the world’s oceans? Write your answer in scientific notation.
kodGreya [7K]

Answer: 7\times10^{19} buckets

Step-by-step explanation:

Given:  A cubic kilometer=10^{15}cubic centimeters

The volume of  world’s oceans=1.4\times10^{9} cubic kilometers of water.

⇒ The volume of  world’s oceans=1.4\times10^{9}\times10^{15} cubic centimeters of water.

Volume of a bucket = 20,000 cubic centimeters of water.

The number of bucket-loads would it take to bucket out the world’s oceans

n=\frac{\text{volume of ocean}}{\text{volume of bucket}}=\frac{1.4\times10^{9}\times10^{15}}{20000}

\Rightarrow\ n=\frac{1.4\times10^{9+15}}{0.2\times10^5}......[a^n\times a^m=a^{m+n}]\\\Rightarrow\ n=7\times10^{24-5}.....[\frac{a^m}{a^n}=a^{m-n}]\\\Rightyarrow\ n=7\times10^{19}

hence,  7\times10^{19} bucketloads would it take to bucket out the world’s oceans.

5 0
3 years ago
What's the answer?????????????
Taya2010 [7]

Answer:

BD = 12 :)

Step-by-step explanation:

Alright, we'll need the Pythagorean theorem for this!

So, the length of AC is 10. That means the lengths of AD and DC are both half of that, which is 5 :)

DC = 5

We already know that BC = 13, so we can plug in these values into the pythagorean theorem for the right triangle BDC:

BD^2 + DC^2 = BC^2

BD^2 + 5^2 = 13^2

BD^2 + 25 = 169

BD^2 = 169 - 25 = 144

BD = √144 = 12 :)

3 0
3 years ago
Jacks average in math for the first nine weeks was an 88 . His second nine weeks average decreased 12.5% what was his average fo
ikadub [295]

10% of 88 = 8.8

2.5% of 88 = 2.2

2.2 + 8.8 = 11

88 - 11 = 77

7 0
3 years ago
Read 2 more answers
I need help fast!!!!!!!!!!!
Vedmedyk [2.9K]

Answer:

Track 2

Step-by-step explanation:

180 degrees would turn the train completely around so if it entered on track 2 then it left on track 2

7 0
3 years ago
In 1981, the Australian humpback whale population was 350 and has increased at a rate of 14% each year since then.)
dimulka [17.4K]

Answer:

In 1981, the Australian humpback whale population was 350

Po = Initial population = 350

rate of increase = 14% annually

P(t) = Po*(1.14)^t

P(t) = 350*(1.14)^t

Where

t = number of years that have passed since 1981

Year 2000

2000 - 1981 = 19 years

P(19) = 350*(1.14)^19

P(19) = 350*12.055

P(19) = 4219.49

P(19) ≈ 4219

Year 2018

2018 - 1981 = 37 years

P(37) = 350*(1.14)^37

P(37) = 350*127.4909

P(37) = 44621.84

P(37) ≈ 44622

There would be about  44622  humpback whales in the year 2018

5 0
3 years ago
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