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velikii [3]
4 years ago
8

Where does meiosis take place in bryophytes

Biology
1 answer:
creativ13 [48]4 years ago
7 0
In the cell system !!!!!
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Does protein synthesis occur frequently in cells? If so, why.
Allisa [31]
Yes because of the E.R.

8 0
3 years ago
Why is it nesscary for the cell to grow and duplicate its dna before the start of meisos
guajiro [1.7K]
<h2><em>the DNA that is packaged into chromosomes must be fully copied. Previous to replication, a germ cell contains two copies of each chromosome, a maternal copy, and a paternal copy. ... DNA replication occurs in the same fashion as it does during mitosis.</em></h2>
3 0
4 years ago
A mature ovum produced from division of a primary oocyte has 18 chromosomes. How many chromatids were present in the primary ooc
a_sh-v [17]

72 chromatids were present in the present in the primary oocyte during  prophase 1 of meiosis.

The primary oocyte contains 72 chromatids during prophase 1 of meiosis as the mature ovum has 18 chromosomes.

The primary oocyte contains 72 chromatids , that means it contains 144 chromosomes. During the first meiotic division, it produces one secondary oocyte and one polar body.

The secondary oocyte  has 72 chromatids, which again undergoes second meiotic division and produces mature ovum and second polar body . The mature ovum contains contains 36 chromatids which means it has 18 chromosomes.

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brainly.com/question/1255767

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6 0
2 years ago
A. Determine the surface area, volume, and surface area to volume ratio for the following three blocks. Then, state which one yo
insens350 [35]

Explanation:

In a cell, the rate of diffusion is higher when the surface area to volume ratio is higher.  

- given that a cube or block has 6 sides...

Volume ⇒ 1.5 cm x 1.5 cm x 1.5 cm= 3.375  cm^{3}

Surface area  ⇒ (1.5 cm x 1.5 cm x 1.5 cm) x 6=13.5   cm^{2}

Surface area :Volume  ⇒ \frac{13.5}{3.75}= 1:4

Volume  ⇒.5 cm x .5 cm x 6 cm= 1.50 cm^{3}

Surface area  ⇒(2 (.5 cm x .5 cm)) + (4(.5 cm x 6 cm))= 0.5+12 = 12.5 cm^{2}

Surface area :Volume ⇒  \frac{12.5}{1.5}= 25: 3

Volume  ⇒3 cm x 2 cm x 2 cm= 12 cm^{3}

Surface area  ⇒(2 (3 cm x 3 cm ))+(4(3 cm x 2 cm))=42  cm^{2}

Surface area :Volume  ⇒  \frac{42}{12}= 7:2

<em>The highest ratio is said to be the most efficient; with a higher surface area, more substances can pass across the surface of the cell at a time. </em>

<em />

Further Explanation:

Cells require all substances to cross the cell membrane. These, like agar, which contains small pores, is semi permeable -only allowing some molecules to pass cross the membrane or surface. The cubes contain a pH indicator that reacts with the solute, vinegar. Cell membranes contain lipids which form a barrier; polarity or arrangement can give these non-polar macromolecules hydrophilic and hydrophobic properties.

Via diffusion, small water molecules can move across the phospholipid bilayer acts as a semi-permeable membrane into the extracross the phospholipid bilayer acts as a semi-permeable membrane into the extracellular fluid or the cytoplasm which are both hydrophilic and contain large concentrations of polar water molecules or other water-soluble compounds. The hydrophilic heads of the bilayer are attracted to water while their water-repellent hydrophobic tails face towards each other- allowing molecules of water and water soluble molecules, to diffuse across the membrane along the concentration gradient

acellular fluid or the cytoplasm which are both hydrophilic and contain large concentrations of polar water molecules or other water-soluble compounds. The hydrophilic heads of the bilayer are attracted to water while their water-repellent hydrophobic tails face towards each other- allowing molecules of water and water soluble molecules, to diffuse across the membrane along the concentration gradient

Thus in smaller cubes the rate of diffusion is higher as the surface area to volume ratio is higher; the vinegar diffuses all the way to the center, as indicated by the color change in the cube.

However as cells increase in size, their surface area:volume ratios decrease rapidly; larger cells, like the larger agar cubes, have a harder time moving molecules across the membrane, so the color change cannot be seen in the middle, as there was less of a permeable surface for the vinegar to diffuse across. to combat this, eukaryotic cells have specialized mechanisms to transport molecules along with membrane-bound organelles like the endoplasmic reticulum that provide a higher surface area for absorption and enable more efficient transportation.

Learn more about membrane components at brainly.com/question/1971706

Learn more about plasma membrane transport at brainly.com/question/11410881

#LearnWithBrainly

4 0
3 years ago
Alguem me ajuda com a primeira lei de Mendel?? Sobre qual era os cuidados que ele usava ao cruzar dois tipos de plantas
miss Akunina [59]

La primera ley es llamada la ley de la uniformidad de los híbridos de la primera generación filial. Y esta dice que al cruzar dos variedades cuyos individuos tienen razas puras ambos homocigotos para un determinado carácter), todos los híbridos de la primera generación son similares.

8 0
4 years ago
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