Answer:
3,432 m²
Step-by-step explanation:
The amount of aluminum in square meters needed to make the mailboxes = 1863(surface area of each mailbox)
Surface area of each mail box = ½(surface area of cylinder) + (Surface area of rectangular prism/box - area of the surface of the box that joins the half-cylinder)
✔️Surface area of ½-cylinder = ½[2πr(h + r)]
r = ½(0.4) = 0.2 m
h = 0.6 m
π = 3.14
Surface area of ½-cylinder = ½[2*3.14*0.2(0.6 + 0.2]
= 0.628(0.8)
Surface area of ½-cylinder = 0.5024 m²
✔️Surface area of the rectangular box/prism = 2(LW + LH + WH)
L = 0.6 m
W = 0.4 m
H = 0.55 m
Surface area = 2(0.6*0.4 + 0.6*0.55 + 0.4*0.55)
Surface area of rectangular box = 1.58 m²
✔️Area of the surface joining the half cylinder and the box = L*W = 0.6*0.4 = 0.24 m²
✅Surface area of 1 mailbox = (0.5024) + (1.58 - 0.24)
= 0.5024 + 1.34
= 1.8424
Amount of aluminum needed to make 1863 mailboxes = 1863 × 1.8424 = 3,432.3912
= 3,432 m²
Answer:
Area:702
perimeter: 114
Step-by-step explanation:
24x27=648
6x9=54
648+54=702
27+24+18+6+9+30=114
First you convert kilograms to pounds,
1 kilogram = 2.205 pounds
next you times the number of pounds per kilogram by the number of kilograms given that need to be turned into pounds.
80 times 2.205 = 176.4
next you subtract to get the answer
176.4 - 135= 41.4
so Ms. Johnson weighs 41.4 pounds less than herr husband
It is d i think dont quote me
Answer:
x = 20
Step-by-step explanation:
The angles shown are alternate exterior angles.
Alternate exterior angles are congruent
This means that 46 must equal 3x - 14
Note that we've just created an equation that we can use to solve for
We now use the equation to solve for x
3x - 14 = 46
add 14 to both sides
3x - 14 + 14 = 46 + 14
simplify
3x = 60
Divide both sides by 3
3x / 3 = x
60 / 3 = 20
We get that x = 20
