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Charra [1.4K]
3 years ago
14

I do not understand this problem PLEASE HELP

Mathematics
1 answer:
PolarNik [594]3 years ago
8 0
Okay, so this question is asking you about a graph (h(t)=-t^2+4t). Because of the -t^2 this will be a parabola that opens downwards. h(t)=-t^2+4t, you can find that the graph will start at zero (since there is no starting value). The easiest way for you to solve this would be if you had a graphing calculator, if you don't then just use an online graphing website. This is a quadratic problem, so they are constructed as AT^2+BT+C, in this problem A=-1,B=4,C=0. To find the vertex, do -(B/2A), which will give you the X value (T value in this case) of the vertex, then you plug that into your graphing toll, and that gives you the vertex. To find the average rate of change between t=2.5 and t=3, you need to find their Y values. Then you find the difference between those values, and multiply it by two, (since their space is 0.5), and that is your AROC (average rate of change). This means that this is the approximated change rate for the graph since it is inconsistent. Hope this helps explain :D
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We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the stu
Molodets [167]

Answer:

The correct option is (c).

Step-by-step explanation:

The complete question is:

The data for the student enrollment at a college in Southern California is:

                    Traditional          Accelerated            Total

                  Math-pathway     Math-pathway

Female              1244                       116                   1360

Male                  1054                       54                    1108

Total                  2298                     170                  2468

We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?

a. 1360/2468 and 116/170

b. 170/2468 and 116/1360

c. 1360/2468 and 170/2468

Solution:

If two events <em>A</em> and <em>B</em> are independent then:

P(A|B)=P(A)\\\\\&\\\\P(B|A)=P(B)

In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.

Consider the following probabilities:

P (F|A) = \farc{116}{170}\\\\P(A|F)=\frac{116}{1360}\\\\P(A)=\frac{170}{2468}\\\\P(F)=\frac{1360}{2468}

If the two events are independent then:

P (F|A) = P(F)

&

P (A|F) = P (A)

But what would not be a valid comparison is:

P (A) = P(F)

Thus, the correct option is (c).

4 0
3 years ago
Pls help me thanks so much
Igoryamba

Answer:

I beileve its no

Step-by-step explanation:

4 0
3 years ago
If the y-intercept of the function y=4x-7 were increased by 10 what would be the equation of the new function
Sonja [21]
The equation would be:
y = 4x + 3

Hope this helps.
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7 0
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The length of a rectangle is 7 centimeters greater than the width.
Lisa [10]

Answer:

length = 17cm, width = 10cm

Step-by-step explanation:

2L + 2w = 54

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7 0
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