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aleksklad [387]
4 years ago
9

Help plzzzz, plzzzz​

Mathematics
2 answers:
Dmitrij [34]4 years ago
8 0
2x +40=4x-10
-2. +10. -2x. +0
50=2x
/2. /2
25=x
Jlenok [28]4 years ago
7 0

Answer:

Step-by-step explanation:

4c+c=90

5c=90

c=90/5=18

∠WMJ=c=18°

∠QMX=4c=4×18=72°

2.

4x+10=2x+40

4x-2x=40-10

2x=30

x=15

vertical angle=2×15+40=70°

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3 years ago
Find the exact value of cos(theta) for an angle (theta) with tan (theta)= -2/3 and with its terminal side in Quadrant II.
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Answer:

-\frac{3\sqrt{13}}{13}.

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Since we are in quadrant two, cosine value is negative while sine value is positive.

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Since cosine and secant are reciprocals then they will have the same sign as along as they both exist.

\sec(\theta)=-\frac{\sqrt{13}}{3}

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I don't see this answer as I'm going to rationalize the denominator.

\cos(\theta)=-\frac{3}{\sqrt{13}} \cdot \frac{\sqrt{13}}{\sqrt{13}}.

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8 0
4 years ago
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Answer:

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Explanation:

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3 years ago
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