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myrzilka [38]
2 years ago
15

What is the surface area of a cylinder with a radius of 5 ft and a height of 2 ft?

Mathematics
1 answer:
icang [17]2 years ago
7 0
\bf \textit{total surface area of a cylinder}\\\\
SA=2\pi r(h+r)~~
\begin{cases}
r=radius\\
h=height\\
-----\\
r=5\\
h=2
\end{cases}\implies SA=2\pi (5)(2+5)
\\\\\\
SA=10\pi (7)\implies SA=70\pi
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Please help me, i don't really understand it...
kenny6666 [7]

Answer:

376.99 (or 377)

Step-by-step explanation:

r=10

h=6

Lateral surface = 2πrh

2π(10)(6)=376.99

Hope this helps!

3 0
3 years ago
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2<br> X - 4<br> =2<br> -11<br> What is the answer
wel

Answer:

-2.5

Step-by-step explanation:

2x-4=-9

2x=-5

x=-2.5

6 0
3 years ago
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Consider Jasper’s balance sheet. Which shows how to calculate Jasper’s net worth? $4,400 - $15,800 = -$11,340 $15,800 + $4,400 =
Jet001 [13]

Answer:

15,800-4,400

Step-by-step explanation:

Add the assets column which equals to 15,800, then add the liability column which adds up to be 4,400 :)

8 0
3 years ago
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Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
2 years ago
A candy shop charges 8.99 a pound it's competitor charges 6.50 for 12 ounces which is a better deal and by how much
Gnom [1K]

Answer:

It is a better deal to do the 6.50 for 12 ounces

Step-by-step explanation:

The reason is because the is 16 ounces in a pound so you would do 8.99/16 and you get .56 per ounce but is you do 6.50/12 you get .54 per ounce which is a better deal.

Hope this helped!!

3 0
3 years ago
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