Answer:
x = 1 , 2.
Step-by-step explanation:
I am assuming these are logs to the base 3.
log3 x + log3 (x^2 + 2) = 1 + 2log3x
-log3 x + log3 (x^2 + 2) = 1
log3 [ (x^2 + 2) / x] = 1 NOTE: 1 = log3 3, so:
log3 [(x^2 + 2) / x] = log3 3
(x^2 + 2) / x = 3
x^2 - 3x + 2 = 0
(x - 1)(x - 2) = 0
x = 1 , 2.
