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Diano4ka-milaya [45]
3 years ago
11

The perimeter of a rectangular garden is 108 meters. The length is 6 meters longer than twice the width, find the dimensions of

the garden

Mathematics
1 answer:
Natalka [10]3 years ago
8 0

Answer:

width=16

length=38

Step-by-step explanation:

perimeter of a rectangle=2(length+width)

108/2=length+ width

54=length+ width

54-width=length

also:

length-6= 2×width

length=2width +6

now you can put the length we found, in the second equation:

54-width=2width+6

54-6=2width+width

48=3width

width=16

now do the exact same thing with one of the equations we created in the beginning.

either this:

54-width=length

or this:

length=2width +6

as the 1st one is simpler, I use that:

54-(16)=length

length=38

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Evaluate each expression a3 for a=5
nadezda [96]
I'm assuming you meant to say a^3. If so, then

a^3 = a*a*a
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4 0
3 years ago
Plz help me with this math and also explain
jasenka [17]

Step-by-step explanation:

<h2>[1]</h2>

  • SI = $250
  • Rate (R) = 12\sf \dfrac{1}{2} %
  • Time (t) = 4 years

\longrightarrow \tt { SI = \dfrac{PRT}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times 12\cfrac{1}{2} \times 4}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times \cfrac{25}{2} \times 4}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times 25 \times 2}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times 50}{100} } \\

\longrightarrow \tt { 250 \times 100 = P \times 50} \\

\longrightarrow \tt { 25000 = P \times 50} \\

\longrightarrow \tt { \dfrac{25000}{50} = P } \\

\longrightarrow \underline{\boxed{ \green{ \tt { \$ \; 500 = P }}}} \\

Therefore principal is $500.

<h2>__________________</h2>

<h2>[2]</h2>

  • 2/7 of the balls are red.
  • 3/5 of the balls are blue.
  • Rest are yellow.
  • Number of yellow balls = 36

Let the total number of balls be x.

→ Red balls + Blue balls + Yellow balls = Total number of balls

\longrightarrow \tt{ \dfrac{2}{7}x + \dfrac{3}{5}x + 36 = x} \\

\longrightarrow \tt{ \dfrac{10x + 21x + 1260}{35} = x} \\

\longrightarrow \tt{ \dfrac{31x + 1260}{35} = x} \\

\longrightarrow \tt{ 31x + 1260= 35x} \\

\longrightarrow \tt{ 1260= 35x-31x} \\

\longrightarrow \tt{ 1260= 4x} \\

\longrightarrow \tt{ \dfrac{1260 }{4}= x} \\

\longrightarrow \underline{\boxed{  \tt { 315 = x }}} \\

Total number of balls is 315.

A/Q,

3/5 of the balls are blue.

\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}x} \\

\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}(315)} \\

\longrightarrow \tt{ Balls_{(Blue)} = 3(63)} \\

\longrightarrow \underline{\boxed{ \green {\tt { Balls_{(Blue)} = 189 }}}} \\

8 0
3 years ago
Another way to check the sum of 104+34+228+877
vekshin1
We are asked to identify an another way to solve the given problem or this summation 104 + 34 + 228 + 887. We can verify it by doing of performing the summation in a reverse sequence such 877 comes first, then followed by 228, then followed by 34 and lastly added by 104. Therefore, the answer is 877 + 228 + 34 + 104.This is an another way to solve the given problem.
4 0
2 years ago
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