Answer:
Step-by-step explanation:
Let's apply the formula (x+y)² = x² + 2xy + y²
Here, x = -a and y = b
So,
= (-a)² + 2(-a)(b) + (b)²
= a² - 2ab + b²
Hence, it has been proved that (-a + b)² = a² - 2ab + b².
Hope this helped!
<h3>~AH1807</h3>
Help please
1 answer:
The first term is a(1) = -3
The recursive step is a(n) = a(n-1)+7 meaning "add 7 to each previous term to get the next term". This points us to the common difference d being 7
a1 = -3
d = 7
an = a1 + d(n-1)
an = -3 + 7(n-1)
an = -3+7n-7
an = 7n-10
Answer:
(it says an = 7n-10 if the image doesn't show up)
Note: the n starts at n = 1
The recursive step is a(n) = a(n-1)+7 meaning "add 7 to each previous term to get the next term". This points us to the common difference d being 7
a1 = -3
d = 7
an = a1 + d(n-1)
an = -3 + 7(n-1)
an = -3+7n-7
an = 7n-10
Answer:
Note: the n starts at n = 1
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