Answer:
Yes this compound could be shown to be butane, specifically, it can be shown to be 9 molecules of butane. Check Explanation for more.
Step-by-step explanation:
Butane contains 10 hydrogen atoms for every 4 carbon atoms. It's molecular formula is C₄H₁₀
The hydrocarbon compound presented has 36 carbon atoms and 90 hyfrogen atoms
If the ratio of each of these atoms present is also in the ratio 4:10 like C:H, then, it can be inferred that the compound is indeed Butane
C | H
36 | 90
dividing through by 9, we have
C | H
4 | 10
which is the exact ratio of Carbon to Hydrogen in butane.
Hence, the unknown compound is most likely 9 molecules of butane
9C₄H₁₀ = 36 carbon atoms and 90 hydrogen atoms.
Hope this Helps!!!
<span><span>9 - 3 = 6, 15-9 = 6 the difference is 6, So d = 6
</span><span>
First term: a1 = 3
Sn = n*(a1 + an)/2
Sn = n*(a1 + a1 + (n-1)*d)/2
Sn = n*(2*a1 + (n-1)*d)/2
</span></span>
<span> <span>substitute 26 for n
</span>
S26 = 26*(2*a1 + (26-1)*d)/2 </span>
<span><span>substitute 3 for a1
</span><span>
S26 = 26*(2*3 + (26-1)*d)/2 </span></span>
<span><span>substitute 6 for d
</span><span>
S26 = 26*(2*3 + (26-1)*6)/2 </span><span>
</span><span>
S26 = 2,028</span></span><span><span>
</span><span>
</span></span>
Complete question :
A population of 30 deer are introduced into a wildlife sanctuary. It is estimated that the sanctuary can sustain 600 deer. The population would grow by 30 percent per year
how many after one year
how many after two years
Answer:
39 deers
51 deers
Step-by-step explanation:
The question can be expressed using the compounding rate formula:
A = P(1+r)^t
A = final population ; P = initial population ; rate, r = 30% = 0.3 ; t = time
After 1 year, t = 1
A = 30(1 + 0.3)^1
A = 30(1.3)^1
A = 39 deers
B.)
After 1 year, t = 2
A = 30(1 + 0.3)^2
A = 30(1.3)^2
A = 50.7
A = 51 deers approximately
Answer:
15
Step-by-step explanation:
1 . (3/4 )*(20/1) put 20 under 1 and multiply across
3*20 = 60
4*1 = 4
2. divide 60 /4 = 15
