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notsponge [240]
4 years ago
14

ANOTHER QUESTION HELPP

Mathematics
1 answer:
PSYCHO15rus [73]4 years ago
4 0
Lower, initial, and at her starting weight
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Alternate interior angles. if you are good at that help ​
mamaluj [8]

Answer:

hi

Step-by-step explanation:

i think so,

(5x-54)⁰=(3x+16)⁰

5x-3x=16+54

2x=70

x=35⁰

3x+16=3×35+16=121

5x-54=5×35-54=121

hope it helps

have a nice day

8 0
3 years ago
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Alex73 [517]
Depends on the amount of cups in the recipe to start with, let’s say it starts with a 1 c recipe, for a 4 c you would need 1 c of lemon juice. So it’s probably.....

1 c of lemon juice
8 0
3 years ago
Solve for x in the simultaneous equation 2x+y=3 ,5x-2y=12
sp2606 [1]

Answer:

x = 2

Step-by-step explanation:

Given the 2 equations

2x + y = 3 → (1)

5x - 2y = 12 → (2)

Multiplying (1) by 2 and adding to (2) will eliminate the y- term

4x + 2y = 6 → (3)

Add (2) and (3) term by term

(5x + 4x ) +( - 2y + 2y) = 12 + 6 , that is

9x = 18 ( divide both sides by 9 )

x = 2

6 0
3 years ago
The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0
3 years ago
Help I just learned how to do this and it’s so hard
Paladinen [302]

Answer: the answer is either the first one or the third not exactly sure

Step-by-step explanation:

7 0
3 years ago
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