125-30=90 degrees in order to find the angle ABC
35,000
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Use cymath it might gives you the answer and shows you how to do it step by step.
Answer:
B 10.211 < 10.210
Step-by-step explanation:
Evaluating each of the given statements one by one:
A 10.345 > 10.340
Decimal values at the tenth and hundredth place are the same on both sides while the thousandth part value is greater on the left side.
Hence, this statement is true
B 10.211 < 10.210
Decimal values at the tenth and hundredth place are the same on both sides while the thousandth part value is greater on the left side.
Hence , this statement is not true because 10.211>10.210
C 9.999 < 10.0
This statement is true because 9.999 is less than 10.
D 6.3 = 6.30
This statement is correct as the left hand side is the same as right hand side.
We use the equation for repeated trials written below:
Probability = n!/r!(n-r)! * p^(n-r) * q^r
The p is the probability of getting a side A in one toss. Since a counter has only two side, p = 0.5. The q is the probability of not getting side A in one toss, which is also q = 0.5. Now, r is the number of success per n trials. There are 3 tosses so, n=3. The question is getting "at least 1" counter. So, r=1, r=2 and r=3.
Probability for r=1: 3!/1!(3-1)! * (0.5)^(3-1) * (0.5)^1= 0.375
Probability for r=2: 3!/2!(3-2)! * (0.5)^(3-2) * (0.5)^2= 0.375
Probability for r=1: 3!/3!(3-3)! * (0.5)^(3-3) * (0.5)^3= 0.125
Total probability = 0.375 + 0.375 + 0.125 = 0.875
