Answer:
The probability of assembling the product between 7 to 9 minutes is 0.50.
Step-by-step explanation:
Let <em>X</em> = assembling time for a product.
Since the random variable is defined for time interval the variable <em>X</em> is continuously distributed.
It is provided that the random variable <em>X</em> is Uniformly distributed with parameters <em>a</em> = 6 minutes and <em>b</em> = 10 minutes.
The probability density function of a continuous Uniform distribution is:

Compute the probability of assembling the product between 7 to 9 minutes as follows:


![=\frac{1}{4}\times [x]^{9}_{7}\\](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B4%7D%5Ctimes%20%5Bx%5D%5E%7B9%7D_%7B7%7D%5C%5C)


Thus, the probability of assembling the product between 7 to 9 minutes is 0.50.
Answer:
so the difference is 84 - 63 = 21.
if we take 84 to be the 100%, what is 21 off of it in percentage?
Step-by-step explanation:
Answer:. No
Step-by-step explanation:
Explanation:
The answer is NO because, mostly, there is always a variability in
the data used in answering statisticall questions. As in the question above, no variability
because Megan is taller than Jim or she is not taller than jim.
Thus, the question is not statistical in nature.
Answer:
62.5% of the parking spaces are taken.
Step-by-step explanation:
Given
To determine
What percent of the parking spaces are taken?
The percentage of taken spaces of the part can be determined using the formula
% of Taken spaces = [Taken spaces / Total Spaces ] × 100
= [1875 / 3000] × 100
= 0.625 × 100
= 62.5%
Therefore, 62.5% of the parking spaces are taken.