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3 years ago

What is an equation for (0,1), (1,3), (2,9), (3,27), (4,81)

Mathematics

1 answer:

Gennadij [26K]3 years ago

4 0

Answer:

$y = 3^x$

Step-by-step explanation:

Each y is 3 times the last one, so it's geometric, so exponential. 3 should appear as the base.

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What is the volume of a cube if the length measures 2 cm?

-BARSIC- [3]

Answer:

=L*b*h

length,berth,highte

=2*2*2

=8cm^3

6 0

3 years ago

Steve paid 10% tax on a purchase of $40. Select the dollar amount of the tax and the total dollar amount Steve paid on the numbe

Shalnov [3]

10% of 40 =
10% × 40 =
.10 × 40 = 4.00

Tax is $4
Amount Paid is 40 + 4 = $44

6 0

3 years ago

Please help and thank you

tatiyna

Answer:

$b_{1}=\frac{2A}{h}-b_{2}$

Step-by-step explanation:

Given: $A=\frac{1}{2}(b_{1} +b_{2})h$

We need to completely isolate $b_{1}$ to solve.

$A=\frac{1}{2}(b_{1} +b_{2})h$

$A=(\frac{1}{2}b_{1} +\frac{1}{2} b_{2})h$

$A=\frac{1}{2}b_{1} h+\frac{1}{2}b_{2}h$

$-\frac{1}{2}b_{1}h+A=\frac{1}{2}b_{2}h$

$-\frac{1}{2}b_{1}h=-A+\frac{1}{2}b_{2}h$

$-\frac{1}{2}b_{1}=\frac{-A}{h}+\frac{1}{2}b_{2}$

Finally, multiply both sides by -2 to completely isolate $b_{1}$ .

$b_{1}=\frac{2A}{h}-b_{2}$

5 0

3 years ago

Read 2 more answers

PLEASE HELP ALSO WILL GET THE BRAINIEST ANSWER!!!! ALSO SHOW YOUR WORK!!!!

MAVERICK [17]

I=PRT
I=Interest
P=principal
R=rate in decimal
T=time in years

1year=12months
72months/12months=6 years
t=6

given
I=8925
P=35000
R=r
T=6

8925=35000*r*6
8925=210000*r
divide both sides by 210000
0.0425=r

the interest rate is 4.25%

6 0

3 years ago

Read 2 more answers

Evaluate the function for the given values to determine if the value is a root. p(−2) = p(2) = The value is a root of p(x).

bija089 [108]

Note: Since you missed to mention the the expression of the function $p(x)$ . After a little research, I was able to find the complete question. So, I am assuming the expression as $p(x)=x^4-9x^2-4x+12$ and will solve the question based on this assumption expression of $p(x)$ , which anyways would solve your query.

Answer:

$p\left(-2\right)=0$

Therefore, $x=-2$ is a root of the polynomial $p(x)=x^4-9x^2-4x+12$

$p\left(2\right)=-16$

Therefore, $x=2$ is not a root of the polynomial $p(x)=x^4-9x^2-4x+12$

Step-by-step explanation:

As we know that for any polynomial let say $p(x)$ , $c$ is the root of the polynomial if $p(c)=0$ .

In order to find which of the given values will be a root of the polynomial, $p(x)=x^4-9x^2-4x+12$ , we must have to evaluate $p(x)$ for each of these values to determine if the output of the function gets zero.

So,

Solving for $p\left(-2\right)$