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3 years ago

5

Someone PLEASE PLEASE HELP!! I need this in one hour!! (20 POINTS) PLEASE SOMEONE HELP

2 answers:

Anettt [7]3 years ago

8 0

Answer:

X=22 (Should make the rest of the problem easy to solve)

Step-by-step explanation:

22x2 + 1 = 45

22 + 5 = 27

45 + 27 = 72 (The perimiter)

vichka [17]3 years ago

6 0

$\large\text{Hello there! :)}$

$\text{Formula for the perimeter: P = 6x + 12}\\\\\text{Dimensions: l = 21, w = 15}\\\\\text{Verification below.}$

$-=-=-==-=-=-=-=-=-=-=-$

$\text{Begin by writing an equation for the perimeter of the rectangle.}\\\\\text{Formula: P = 2l + 2w}\\\\P = 2(2x + 1) + 2(x + 5)\\\\P = 4x + 2 + 2x + 10\\\\\text{Combine like terms:}\\\\\boxed{P = 6x + 12}\\\\\text{Solve for the dimensions:}\\\\72 = 6x + 12\\\\\text{Subtract 12 from both sides:}\\\\60 = 6x\\\\\text{Divide both sides by 6:}\\\\x = 10\\\\\text{Substitute in 10 for x in the equations for each side length:}\\\\l = 2x + 1\\\\l = 2(10) + 1\\\\\boxed{l = 20 + 1 = 21units}$

$w = (10) + 5\\\\\boxed{w = 15 units}$

$\text{Use the formula for the area of a rectangle to verify. A = l * w:}\\\\\boxed{A = 15 * 21 = 315 units^{2} }$

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WITCHER [35]

Answer:

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Step-by-step explanation:

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(a) Let,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}$

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$f(x,y,z)=xyz+h(z)$

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$h'(z)=6z\implies h(z)=3z^2+C$ (By integrating h'(z)) where C is integration constant. Hence,

$f(x,y,z)=xyz+3z^2+C$

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Answer:

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