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3 years ago

I need help on what the area of the shape is because they didn’t tell us how to find it

Mathematics

1 answer:

Leto [7]3 years ago

8 0

Answer:

The area of the shape (trapezoid) is 55 square feet.

Step-by-step explanation:

The formula to get the area of a trapezoid is $((b_{1} +b_{2} )/2)*h$ . b1 is one of the bases, b2 is the other and h is the height.

First, you need to find the average of the bases:

(15+7=22)/2=11

Then, you multiply that by the height.

11*5=55

Lastly, you add the units.

55 square feet is the answer

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Find the value of x.

sveticcg [70]

If 98 - 32 = 66,

then x = 66°

7 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B5%7D%2B%5Cfrac%7B3x%7D%7B15%7D%3D%5Cfrac%7B2x%7D%7B3%7D%20%7D%20" id="TexF

Bezzdna [24]

Multiply all terms by 15
3x+3x= 10x+30

Combine like terms
6x=10x+30

Subtract 10x from both sides
-4x=30

Divide both sides by -4
x= -7.5

Final answer: -7.5

4 0

3 years ago

In a binomial distribution, n = 8 and π=0.36. Find the probabilities of the following events. (Round your answers to 4 decimal p

skelet666 [1.2K]

Answer:

$\mathbf{P(X=5) =0.0888}$

P(x ≤ 5 ) = 0.9707

P ( x ≥ 6) = 0.0293

Step-by-step explanation:

The probability of a binomial mass distribution can be expressed with the formula:

$\mathtt{P(X=x) =(^{n}_{x} ) \ \pi^x \ (1-\pi)^{n-x}}$

$\mathtt{P(X=x) =(\dfrac{n!}{x!(n-x)!} ) \ \pi^x \ (1-\pi)^{n-x}}$

where;

n = 8 and π = 0.36

For x = 5

The probability $\mathtt{P(X=5) =(\dfrac{8!}{5!(8-5)!} ) \ 0.36^5 \ (1-0.36)^{8-5}}$

$\mathtt{P(X=5) =(\dfrac{8!}{5!(3)!} ) \ 0.36^5 \ (0.64)^{3}}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 \times 5!}{5!(3)!} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 }{3 \times 2 \times 1} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =({8 \times 7 } ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =0.0887645}$

$\mathbf{P(X=5) =0.0888}$ to 4 decimal places

b. x ≤ 5

The probability of P ( x ≤ 5) $\mathtt{P(x \leq 5) = P(x = 0)+ P(x = 1)+ P(x = 2)+ P(x = 3)+ P(x = 4)+ P(x = 5})$

${P(x \leq 5) = ( \dfrac{8!}{0!(8!)} \times (0.36)^0 \times (1-0.36)^8 \ ) + \dfrac{8!}{1!(7!)} \times (0.36)^1 \times (1-0.36)^7 \ +$ $\dfrac{8!}{2!(6!)} \times (0.36)^2 \times (1-0.36)^6 \ + \dfrac{8!}{3!(5!)} \times (0.36)^3 \times (1-0.36)^5 + \dfrac{8!}{4!(4!)} \times (0.36)^4 \times (1-0.36)^4 \ + \dfrac{8!}{5!(3!)} \times (0.36)^5 \times (1-0.36)^3 \ )$