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3 years ago

What is the value of f(1)? ОООО

Mathematics

2 answers:

mamaluj [8]3 years ago

5 0

Answer:

Step-by-step explanation:

For this case the first thing that we must observe is the value of f (x) of the function in the table, when the value of x is x = -1

We then have that for x = -1, the value of the function is equal to 0.

nordsb [41]3 years ago

3 0

Answer:

Step-by-step explanation: Any variable that is by itself always =1

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Simplify: -1 | 2/3 - 4 | / 5/6

stealth61 [152]

Answer:

Step-by-step explanation:

$- 1 | \frac{2}{3} - 4| \div \frac{5}{6} \\ - 1 | \frac{2}{3} - \frac{4 \times 3}{1 \times 3} | \div \frac{5}{6} \\ - 1 | \frac{2 - 12}{3} | \div \frac{5}{6} \\ - 1 | \frac{ - 10}{3} | \div \frac{5}{6} \\ \frac{10}{3} \div \frac{5}{6} \\ \frac{10}{3} \times \frac{6}{5} \\ \frac{2}{1} \times \frac{2}{1} = 4$

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2 years ago

A washer and dryer cost a total of $1152. The cost of the washer is two times the cost of the dryer. Find the cost of each item.

ASHA 777 [7]

Answer: 576 for both

Step-by-step explanation:

5 0

3 years ago

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45 points to answer this question

Mrac [35]

if a = b and b = c, then a = c.

In this case if y = - 7 and -7 = z then y = z .................>(y = a, -7 = b and z = c)

Answer: B)

transitive property of equality

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3 years ago

Which one of the following tables is a relation that represents a function?

TiliK225 [7]

C is the correct answer homie

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3 years ago

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Use the rational root theorem to list all possible rational roots for the equation.

Alik [6]

Answer:

The possible rational roots are

$\pm 1, \pm 2,\pm3,\pm6,\pm \frac{1}{3},\pm \frac{2}{3}$

Step-by-step explanation:

We have been given the equation 3x^3+9x-6=0 and we have to list all possible rational roots by rational root theorem.

The factors of constant term are $1, 2, 3,6$

The factors of leading coefficient are $1,3,$

From ration root theorem, the possible roots are the ratio of the factors of the constant term and the factors of the leading coefficient. We include both positive as well as negative, hence we must include plus minus.

$\pm\frac{1,2,3,6}{1,3}\\\\ =\pm 1, \pm 2,\pm3,\pm6,\pm \frac{1}{3},\pm \frac{2}{3}$

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3 years ago

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