A(n)=-6-4(n-1) Find the 4th term in the sequence

2 answers:

8 0

All we have to do is replace n with 4.
-6-4(4-1)
Parenthesis first.
-6-4×3
Multiplication next.
-6-12
Now subtract.
-18
The 4th term is -18.
Tell me if this helps!!

blsea [12.9K]3 years ago

3 0

Answer: -18

Step-by-step explanation:

Tp find the fourth term, it means

n= 4

so we will put n= 4 in aₙ= -6 - 4(n - 1)

a₄ = -6 -4 (4-1)

Following the BODMAS rule

a₄ = -6 -4(3)

a₄ = -6 - 12 = -18

Therefore the fourth term in the sequence is -18

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What is the area of a circle with a Radius of 4 and a Diameter of 2?<br><br> (Its on Khan)

algol13

Answer:4^2≈50.26548

Step-by-step explanation:

πr2.

Where r is the radius and π≈3.14 , the ratio of a circle's circumference to its diameter.

Plugging in 4 from the radius, we get.

42π

⇒16π inches.

This is our exact answer. Alternatively, we can plug in 3.14 for π to get.

50.26 inches.

7 0

2 years ago

Please Help!

alisha [4.7K]

Diagonal of the parallelogram divides the parallelogram in to two equal areas.

So area of parallelogram = 2(area of triangle)

According to the given diagram,

AB= 8, AD = 5 and BD = 11

So according to the Heron's formula,

Area of triangle = $\sqrt{s(s-a)(s-b)(s-c)}\\\\where,\\ s =\frac{a + b + c }{2}$

and a, b and c are the three sides of the triangle

Area of triangle ABD = $s=\frac{8 + 5 + 11}{2} \\\\s = \frac{24}{2}\\\\s = 12Area of triangle ABD = \sqrt{12(12 - 8) (12 - 5) (12 - 11)}\\\\Area of triangle ABD = \sqrt{12(4) (7) (1)}\\\\Area of triangle ABD = \sqrt{336}\\\\Area of triangle ABD = 18.33$