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vekshin1
3 years ago
7

simplify the expression by combining the terms, write the terms from highest to the lowest power of the variable 4y^2+y^2-3y-6+1

4y^2-2+4y-7y
Mathematics
1 answer:
Artyom0805 [142]3 years ago
4 0
You have to combine like terms.

Like terms are those with the same letters raised to the same power.

These are the sums of the like terms:

1) 4y^2 + y^2 + 14y^2 = 19y^2

2) - 3y + 4y - 7y = - 6y

3) - 6 - 2 = - 8

Simplified expression: 19y^2 - 6y - 8<------------ answer
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Chen kept track of how many baskets were made in a basketball game. After 6 minutes, 5 baskets were made. How long did it take u
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Assuming the same pace was kept, it would take 9.6 minutes.

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The last one would be incorrect. We are looking for PART of whatever N is. Multiply by the whole number 25 is definitely not what we want to do. 

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3 years ago
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Directions: Complete all 3 questions. Make sure you include a graph, work and conclusion.
Simora [160]

Prove that the quadrilateral whose vertices are I(-2,3), J(2,6), K(7,6), and L(3, 3) is a rhombus.

I think in these problems the first step is to express each side as a vector.  A vector is the difference between points.  When two sides have the same vector (or negatives) it means they're parallel and congruent.  So in a rhombus IJKL the vectors IJ and LK should be the same, as should JK and IL.  That much assures a parallelogram; we check IJ and JK are congruent to complete the crowing of the rhombus.

Let's calculate these vectors:

IJ = J - I = (2,6) - (-2,3) = (2 - -2, 6 - 3) = (4, 3)

LK = K - L = (7, 6) - (3, 3) = (4, 3)

IJ = LK, so far so good

(Note: If you haven't got to vectors yet you can just show the two sides are the same length, 5, and have the same slope, 3/4, both of which can be read off the vectors.)

JK = K - J = (7,6) - (2,6) = (5,0)

IL = L - I = (3, 3) - (-2, 3)  = (5, 0)

Those are the same too.    

Now we have to show IJ ≅ JK

The length of IJ is the cliche √4²+3² = 5, the same as JK, so IJ ≅ JK

We showed all four sides are congruent and we have two pair of parallel sides, so we have a rhombus.

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