Answer:
Option b that is 1.33 is the right choice.
Step-by-step explanation:
Given:
Mean rate of arrival
= 8 planes/hr
Service time =
minute/plane
Mean service rate
=
=
planes/hr
Applying the concept Poisson-distributed arrival and service rates (exponential inter-arrival and service times)(M/M/1) process:
We have to find mean number of planes waiting to land that is mean number of customers in the queue .
Mean number of customers in queue
.
⇒
Considering,
,
is also mean number of customers in service.
⇒ ![L_q=\frac{ \lambda^2}{\mu(\mu-\lambda)}](https://tex.z-dn.net/?f=L_q%3D%5Cfrac%7B%20%5Clambda%5E2%7D%7B%5Cmu%28%5Cmu-%5Clambda%29%7D)
⇒ Plugging the values.
⇒ ![L_q=\frac{8^2}{12(12-8)}](https://tex.z-dn.net/?f=L_q%3D%5Cfrac%7B8%5E2%7D%7B12%2812-8%29%7D)
⇒ ![L_q=\frac{64}{48}](https://tex.z-dn.net/?f=L_q%3D%5Cfrac%7B64%7D%7B48%7D)
⇒
So,
Mean number of planes in holding and waiting to land = 1.33
Q. why did the cow cross the road a. to watch the mooooviies
G(f(x)) is puting f(x) inside g(x) for x
= (-2x+3)² + 5
= (-2x + 3)(-2x+3) + 5
= 4x² - 6x - 6x + 9 + 5
= 4x² - 12x + 14
c.
Answer:
<h2>26% as a fraction is 13/50 and as a decimal is 0.26</h2>
Step-by-step explanation: