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lesya692 [45]
3 years ago
13

I need help with this Question for school

Mathematics
1 answer:
bazaltina [42]3 years ago
4 0

Answer:

77 = 1 x 77 or 7 x 11.

Step-by-step explanation:

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7.9x – 2 – 3.2x – 10 = 2.8 + x
ryzh [129]

Answer:

x=4

Step-by-step explanation:

combine like terms

divide to get the x by itself

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2 years ago
6. Find both solutions by factoring <br> ): 3x^2 + 10x + 7 = 0
timama [110]
Both solutions:
x = -1, -7/3
7 0
2 years ago
Hi guys, can anyone help me with this triple integral? Many thanks:)
Crank

Another triple integral.  We're integrating over the interior of the sphere

x^2+y^2+z^2=2^2

Let's do the outer integral over z.   z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

y^2=4-x^2-z^2

x is the inner integral so at this point we conservatively say its zero.  That means y goes from -\sqrt{4-z^2} and +\sqrt{4-z^2}

Similarly the inner integral x goes between \pm-\sqrt{4-y^2-z^2}

So we rewrite the integral

\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz

Let's work on the inner one,

\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz

There's no z in the integrand, so we treat it as a constant.

=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}

So the middle integral is

\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy  

I gotta go so I'll stop here, sorry.

7 0
2 years ago
Read 2 more answers
PLEASE ANSWER I WILL GIVE YOU BRAINIEST IF CORRECT!!!!!!!<br> thanks!
Flauer [41]

Answer:

700 is your answer

Step-by-step explanation:

ok so 5x120=600 +100=700 so 700 is your answer

8 0
3 years ago
fred purchased 6 shirts on friday. kyle purchased 4 shirts and a pair of shorts for $25. they paid the same amount for each shir
Mars2501 [29]

Answer:

Step-by-step exp$ . 4 :33

3 0
3 years ago
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