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3 years ago

I need help with this Question for school

Mathematics

1 answer:

bazaltina [42]3 years ago

4 0

Answer:

77 = 1 x 77 or 7 x 11.

Step-by-step explanation:

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7.9x – 2 – 3.2x – 10 = 2.8 + x

ryzh [129]

Answer:

x=4

Step-by-step explanation:

combine like terms

divide to get the x by itself

5 0

2 years ago

6. Find both solutions by factoring <br> ): 3x^2 + 10x + 7 = 0

timama [110]

Both solutions:
x = -1, -7/3

7 0

2 years ago

Hi guys, can anyone help me with this triple integral? Many thanks:)

Crank

Another triple integral. We're integrating over the interior of the sphere

$x^2+y^2+z^2=2^2$

Let's do the outer integral over z. z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

$y^2=4-x^2-z^2$

x is the inner integral so at this point we conservatively say its zero. That means y goes from $-\sqrt{4-z^2}$ and $+\sqrt{4-z^2}$

Similarly the inner integral x goes between $\pm-\sqrt{4-y^2-z^2}$

So we rewrite the integral

$\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz$

Let's work on the inner one,

$\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz$

There's no z in the integrand, so we treat it as a constant.

$=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}$

So the middle integral is

$\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy$

I gotta go so I'll stop here, sorry.

7 0

2 years ago

Read 2 more answers

PLEASE ANSWER I WILL GIVE YOU BRAINIEST IF CORRECT!!!!!!!<br> thanks!

Flauer [41]

Answer:

700 is your answer

Step-by-step explanation:

ok so 5x120=600 +100=700 so 700 is your answer

8 0

3 years ago

fred purchased 6 shirts on friday. kyle purchased 4 shirts and a pair of shorts for $25. they paid the same amount for each shir

Mars2501 [29]

Answer:

Step-by-step exp$ . 4 :33

3 0

3 years ago