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3 years ago

Please help 4th grade 3 questions

Mathematics

2 answers:

Vlada [557]3 years ago

5 0

Answer:

good luck

Step-by-step explanation:

1- a

2- c

3- b

ivanzaharov [21]3 years ago

4 0

b for number 1 do u need all of them

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Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

1 year ago

What is the value of x? (X+40)

ozzi

-40

Step-by-step explanation:

at the moment your equation is x+40=0

you move the forty to the other side by subtraction and you get x= -40

7 0

3 years ago

Read 2 more answers

Solve for V: V/9+-5 = 2

Vesna [10]

V=63

V-45=18

V=18+45

V= 63

6 0

4 years ago

Solve the proportion

Elena-2011 [213]

To solve this, you need to cross multiply the fractions.

Let’s say you have these fractions:
A / B = C / D

To cross multiply, multiply the denominator of the first fraction (B) by the numerator of the second fraction (C). Multiply the numerator of the first fraction (A) by the denominator of the second fraction (D).

You get B x C = A x D

After cross multiplying your fractions, you get 63 = 7(c +4)

Distributing the 7 into c+4 gives you this:
63 = 7c + 28

Now solve this like a normal equation with a variable

63 = 7c + 28
35 = 7c
5 = c

To double check that, plug c = 5 into the original equation.

1/(5) + 4 = 7/63
1/9 = 7/63

7/63 simplifies into 1/9 (7:7 = 1, 63/7 = 9)

1/9 = 1/9 so c = 5 is correct

8 0

3 years ago

F(x)=- x ^ 2 - 1,x ne5\\ -3,x=5 lim x -> 5 f(x) = lim x -> 5 f(x) Find if

Wewaii [24]

Answer:

the answer to the question is 1

3 0

2 years ago