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viktelen [127]
3 years ago
5

Every day of the week Sam's

Mathematics
1 answer:
valina [46]3 years ago
8 0
34-13.6=20.4
20.4/34= .60
60% off
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Square Root
Lynna [10]

Answer:

Domain: [0,infinity)

Range: [0,infinity)

X-intercept: (0,0)

Y-intercept: (0,0)

Step-by-step explanation:

5 0
3 years ago
The equation of line AB is (y-3) = 5 (x - 4). What is the slope of a line perpendicular to line AB?
Nastasia [14]
Y - 3 = 5(x - 4)
y - 3 = 5x - 20
y = 5x - 20 + 3 = 5x - 17
=> slope = 5

For perpendicular line, m2 = -1/m1 = -1/5
5 0
3 years ago
Read 2 more answers
One example of US foreign aid is
Zolol [24]
One is Iraq! :) (Hope this helps!)
8 0
3 years ago
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Christina paints canvases and sells the pieces at craft fairs. The function c(t) approximates how many canvases she paints per h
dsp73

Answer:

The units of measurement for the composite function c(w(h)) is canvases over weeks.

Step-by-step explanation:

Given :

The function c(t) approximates how many canvases she paints per hour.

The function w(h) represents how many hours per week Christina spends painting the canvases.

To Find: What are the units of measurement for the composite function c(w(h))?

Solution:

C(t)= canvases paints per hour

W(h)=hours per week

C(w(h)) =canvases paints per hour * hours per week

C(w(h)) =canvases per week

So, Option 3 is true

Hence , the units of measurement for the composite function c(w(h)) is canvases over weeks.

7 0
4 years ago
The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented
leva [86]

The equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: \frac{x^{2}}{a^{2}}  - \frac{y^{2}}{b^{2}}    = 1

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

d= \frac{a^{2}}{c}

Here the directrix line is given as : x= 2304/50

Thus, \frac{a^{2}}{c}  = \frac{2304}{50}

⇒ \frac{a^{2}}{50}  = \frac{2304}{50}

⇒ a² = 2304

⇒ a = √2304 = 48

For hyperbola, b² = c² - a²

⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

⇒ b² = 2500 - 2304

⇒ b² = 196

⇒ b = √196 = 14

So, the equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

5 0
3 years ago
Read 2 more answers
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